I get the int and store it in n. The switch statement takes inside its parenthesis an int or a char or some primitive type.
我得到一个整数并把它存储，到n中，switch语句的圆括号里可以是一个整数，或者一个字符或其他的基本类型。
Type: Gets the static type of the expression. In this case, the expression is of type Func<int, int, int>.
Type：得到表达式的静态类型，在本例中，表达式的类型是Func<int, int, int>。
If the first two arguments to find are of type int* and the third is of type int, then it is as if you had called the following function.
如果前面两个参数类型是int*，第三个参数类型是int，那么就像调用下面的函数一样。
Create a UML operation named purevirtualop with a return parameter of type int and a parameter x of type int.
创建一个名为purevirtualop的UML操作，其返回值类型为int，参数x 的类型为 int。
Although it does not provide a type int, it doesn't suffer from the ambiguities that have always arisen from ranges of int on different platforms.
虽然它没有提供int类型，但它不会受到int在不同平台上的取值范围不同所带来的多义性的困扰。
Note that int y(2.3) is allowed in C++0x; no type narrowing is assumed, and y equals 2 while int y{2.3} is plain error.
注意，在 C++0x 中允许inty(2.3)；由于不允许类型窄化，y等于2，而 int y{2.3}是错的。
Equally clearly, int or double may not: find uses the expression *first, and the dereference operator makes no sense for an object of type int or of type double.
同样的，或者不是int和double：find使用表达式 *first，这个废弃的操作使int对象或者double对象没有意义。
Equally clearly, int or double may not: find uses the expression *first, and the dereference operator makes no sense for an object of type int or of type double.
同样的，或者不是int和double：find使用表达式 *first，这个废弃的操作使int对象或者double对象没有意义。
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