Pauli says no two electrons in a given system can have the entire set of quantum numbers identical.
泡利说在一个给定的系统内，没有两个电子有完全相同的量子数。
So now we're just counting up our orbitals, an orbital is completely described by the 3 quantum Numbers.
所以现在我们只要把这些轨道加起来，一个轨道是由3个量子数完全确定的。
So each electron has a distinct set of quantum Numbers, the first important idea.
每个电子的量子数，是不尽不同的，对于这第一个重要观点。
Remember, we need those three quantum Numbers to completely describe the orbital.
要知道，我们需要三个量子数，才能完全描述一个轨道。
The same place is that energy is a function of these four quantum numbers.
它就是这个结论,能量是这四个量子数的机能显示。
He has two electrons here with the same set of quantum Numbers. B but these are two separate hydrogen atoms.
因为我写了两个量子数，一样的电子，但这是在两个不同原子中啊。
Under the laws of quantum mechanics, the nuclei of atoms have shell-like structures analogous to the spheres in which given Numbers of electrons exist in certain orbits around the nucleus.
根据量子力学的法则，核子外部一定数目的核外电子以一定的圆周轨道运行形成球状壳结构。
And so the sum over all microstates, then, becomes the sum over all possible combinations of quantum Numbers.
于是就化为，对所有可能的量子数的组合求和。
How many different orbitals can you have that have those two quantum Numbers in them?
有多少个轨道是，含有这两个量子数的？
And I just want to point out that now we have these three quantum Numbers.
我想指出的是，现在我们有了，这3个量子数。
Pauli So, here, Pauli came out on top, we say, and he's known for the Pauli exclusion principle, which tells us that no two electrons in the same atom can have the same four quantum Numbers.
在这里是，他因为Pauli不相容原理而出名，这个原理是说同一个原子中的两个电子，不能有相同的第四量子数。
OK, great. So, most of you recognize that there are four different possibilities of there's four different electrons that can have those two quantum Numbers.
大部分都认为，有4个不同的可能，有四个不同的电子可以有，这两个量子数。
But, as I said before that, we have some more quantum numbers, when you solve the Schrodinger equation for psi, these quantum numbers have to be defined.
但我说了，我们还有，其它的量子数，当你解，psi的薛定谔方程时，必须要，定义这些量子数。
So, those are our three quantum numbers.
这就是，3个量子数。
n l So negative e, which is sub n l, because it's a function of n and l in terms of quantum numbers.
也就是负的，E，下标是，因为它是一个,关于量子数，n，和，l，的函数。
R And we abbreviate that by calling it r, l by two quantum numbers, and an l as a function of little r, radius.
我们把它简称为，两个指定的量子数n和，它是半径小r的函数。
The reason there are three quantum Numbers is we're describing an orbital in three dimensions, so it makes sense that we would need to describe in terms of three different quantum Numbers.
我们需要，3个量子数的原因，是因为我们描述的是一个，三维的轨道，所以我们需要，3个不同的量子数，来描述它。
So you'll notice in your problem-set, sometimes you're asked for a number of orbitals with a set of quantum Numbers, sometimes you're asked for a number of electrons for a set of quantum Numbers.
希望你们在做习题的时候注意到，有时候问的是拥有，一套量子数的轨道数，有时候问的是拥有一套，量子数的电子数。
what three quantum numbers tell us, versus what the fourth quantum number can fill in for us in terms of information.
三个量子数和,四个量子数告诉我们的信息。
So let's go to a second clicker question here and try one more. So why don't you tell me how many possible orbitals you can have in a single atom that have the following two quantum numbers?
让我们来看下一道题目,你们来告诉我,有多少个可能的轨道,含有这些量子数呢？
In the limit of large quantum Numbers quantum mechanics goes over into classical mechanics.
在大量子数的极限情况下，从量子力学过渡到经典力学。
The sign reversal applies only to quantum numbers (properties) which are additive, such as charge, and not to mass, for example.
举例来说正负号只适用于附加量子数，例如电荷，而不是质量。
And Pauli says no two electrons in a given system can have the entire set of quantum Numbers identical.
而泡利认为在一个给定的系统内，没有两个电子有完全相同的量子数。
It is proved that the average photon Numbers and the second-order quantum coherence are dramatically influenced by the entangled degree of the atoms.
分析原子的纠缠度对约化后光场性质的影响，结果表明纠缠度强烈影响光场的平均光子数分布和二阶量子相干性。
The process is a purely diffractive process since no quantum numbers exchange between the two colliding particles.
由于两个碰撞粒子之间没有量子数的交换，因此该过程是一个单纯的绕射过程。
This is often expressed by saying that in case of large quantum numbers quantum mechanics "reduces" to classical mechanics and classical electromagnetism .
通常可以表示为大量子数目情形下量子力学“减少”到经典力学和经典电磁学。
So if we're talking about the fourth excited state, and we talk instead about principle quantum numbers, what principle quantum number corresponds to the fourth excited state of a hydrogen atom.
如果我们说的是，第四激发态，我们用，主量子数来描述，哪个主量子数对应了，氢原子的第四激发态？
Using this identification, we read off the quantum Numbers of the quarks.
照此鉴定，可以识别出夸克的量子数。
Using this identification, we read off the quantum Numbers of the quarks.
照此鉴定，可以识别出夸克的量子数。
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