How does an uninitialized variable get a random value?
未初始化变量是如何得到一个随机的价值？
Is initializing a variable with an uninitialized variable legal?
正在初始化一个变量未初始化的变量的法律？
In addition, incrementing an uninitialized variable is much slower than if it was initialized.
另外，对一个没有初始化的变量进行递增操作要比初始化过的来得慢。
Sometimes, we're lucky and using an uninitialized variable results in an immediate crash at run time.
有时我们很幸运，使用未初始化的变量导致程序在运行时突然崩溃。
You will get an E_NOTICE any time an uninitialized variable is used in a way that assumes it has a value.
每当使用未初始化的变量（假定具有值）时，您将得到一条 E_NOTICE。
Hence, with no password entered, the function is passed an uninitialized variable and a script error results.
因此，若无密码键入，传递到该函数的是未初始化的变量和脚本错误结果。
To make it uninitialized you have to spend extra effort and type "int i = void;" expressing that the uninitialized variable is intentional and not due to laziness.
要想不对i进行初始化，你需要额外的输入“int i =void;”来表示你是有意不对i进行初始化而不是因为疏忽大意。
This will result in PHP reporting a warning every time an uninitialized variable is used, each bad file access, and other (mostly) harmless errors, but might also represent a potential attack vector.
设置更改后，每当使用未初始化的变量、进行错误的文件访问及发生其他（大多数）无害错误时，PHP都会报告一条警告消息，但也存在这是一个潜在攻击矢量的可能性。
Otherwise, the variable will be uninitialized when it is used.
否则，该变量在使用时将是未初始化的。
The expression in an assign accesses an uninitialized part of a variable.
赋值中的表达式访问变量的未初始化部分。
For example, in C and C + +, if you write "int I;" the variable is uninitialized.
例如，在C和C+ +中，如果你写“inti；”则变量是没有被初始化的。
For example, in C and C + +, if you write "int I;" the variable is uninitialized.
例如，在C和C+ +中，如果你写“inti；”则变量是没有被初始化的。
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