The answer was: at any time t, the location of the particle is given by this formula.

答案是,在任意时刻 t,这个质点的位移都由这个式子给出

耶鲁公开课 - 基础物理课程节选

Consequently, for this object the position y, at any time t is known to be 15+10t-5t^.

因此,对这个物体来说,在任意时刻的位移y,就应该为15+10t-5t^

耶鲁公开课 - 基础物理课程节选

I think you can tell by analogy with what I did in one dimension that the position of that object at any time t is going to be the initial position plus velocity times t plus one half a t square.

你们可以类比一下我在一维情况下的结论,这个物体在任意时刻 t 的位移,等于初始位移,加上 v ? t + 1/2 ? a ? t^2

耶鲁公开课 - 基础物理课程节选