In traditional Pig Latin, the first consonant sound of a word is moved to the end of the word and then an -ay is added to that.
VOA: special.2009.12.04
Ay me!" he says as he realizes, of course, there will be no flowers.
唉,悲惨啊!“,他突然意识到,当然不会有鲜花。
Look at line fifty-five: "Ay me, I fondly dream! / ?" Had ye been there -- for what could that have done?"
看第55行:“哎,我啊!,我在痴呆的幻想/,如果你们女神们在那儿,又能怎样呢“
VOA: special.2010.01.06
Therefore, the vector A that you gave me, I have managed to write as i times Ax plus j times Ay.
这样,你给我的矢量 A,我已把它写成 i ? Ax + j ? Ay的形式
You can ask yourself, "If you gave me a particular vector, what do I use for Ax and Ay?"
你可以问问自己,"如果给定一个矢量,该怎么确定 Ax 和 Ay"
But this is the same vector we are calling i times Ax plus j times Ay.
这和矢量 i ? Ax + j ? Ay 是一样的
The point is the arrow A, somebody has chosen to write in terms of i prime and j prime as Ax prime and Ay prime.
解决问题的关键在于矢量 A,可以用这样的形式来描述,i' ? Ax' + j' ? Ay'
In practice, most of the time we work with these two numbers, Ax and Ay.
在实际过程中,大多数时间我们就用 Ax 和 Ay 来计算
If the Ax and Ay, some are positive and some are negative, this is the way by which we have learned we should combine multiples of i.
如果 Ax 和 Ay 有正有负,这就要用到我们所学过的方法,将所有 i 的倍数加起来
But Ax prime and Ay prime will continue to be the coefficients.
但系数仍然是 Ax' 和 Ay'
If you give me a pair of numbers, Ax and Ay, that's as good as giving me this arrow, because I can find the length of the arrow by Pythagoras' theorem.
如果给我一组数字,Ax 和 Ay,就相当于给了我这个箭头示意图,因为我可以利用毕达哥拉斯定理定理求出模长
That would come by saying, "I'm taking i times Ax + j times Ay + i times Bx + j times By, " and I'm trying to add all these guys.
那就这样做,"i ? Ax + j ? Ay + i ? Bx + j ? By",然后把它们都加起来
satisfies the condition tan is Ay over Ax..
满足其正切等于 Ay 除以 Ax
Now, when you work with components, Ax and Ay, if I didn't mention it, they are the components of the vector, you can do all your bookkeeping in terms of Ax and Ay.
当你们在计算分量 Ax 和 Ay 的时候,即使我没有说明,你们也要记得它们是矢量的分量,你们可以都用 Ax 和 Ay 的形式来表示
Then j with Ay + By.
同样有平行于 j,模长为 Ay + By 的矢量
A very important result is that if two vectors are equal, if A = B, the only way it can happen is if separately Ax is equal to Bx and Ay is equal to By.
这里有一个相当重要的结论,如果两个矢量相等,例如 A = B,那么当且仅当,Ax = Bx 和 Ay = By 分别成立
I gave you a law of transformation of the components; namely, if the vector has components Ax and Ay in one reference frame and Ax prime and Ay prime in another reference frame, how are the two related?
我介绍过分量变换的法则,即如果矢量在一个坐标系的分量为 Ax 和 Ay,在另一坐标系中的分量为 Ax' 与 Ay',它们有着什么样的联系
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