Knowing that, I'm going to say, OK, how many pigs are there, well that's just how we're, however many I had total, minus that amount, and then I can see, how many legs does that give, and then I can check, that the number of legs that I would get for that solution, is it even equal to the number of legs I started with, ah! Interesting. A return.

它将给我返回头的总数，知道了这些之后我可以说好了,有多少猪呢，无论有多少组鸡的数目，我只要用总数减去那个值,之后我就可以知道一共有多少条腿,然后再把这个值和题目中的腿数相比较，看它是否等于一开始的腿数,啊！真有趣，有一个返回值。

麻省理工公开课 - 计算机科学及编程导论课程节选

For an angular node, we're just talking about what the l value is, so whatever l is equal to is equal to the number of angular nodes you have.

对于角向节点，我们其实就是在讨论l，的值是多少，因此不管，l，的值等于几,它就等于你所有的角向节点的数目。

麻省理工公开课 - 化学原理课程节选

Z Number of protons in the nucleus, this is number of protons in the nucleus, which in the neutral atom is equal to the number of electrons.

质子数。，Z，proton，number。,原子核中的质子数，这是原子核的质子数，在中性原子中，等于,电子数。

麻省理工公开课 - 固态化学导论课程节选

The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

我们可以用叫做,键序的概念来弄明白它，键序等于1/2乘以成键电子,数目减去反键电子数目。

麻省理工公开课 - 化学原理课程节选

The number of electrons in an atom is deduced to be approximately equal to half the atomic weight.

原子中的电子数,将近是原子质量的一般。

麻省理工公开课 - 固态化学导论课程节选

So, if you look at all of these, we have full octets for all of them, and if we count up all of the valence electrons, it's going to be equal to our number 26 here.

那么，如果大家看看所有的这些，它们的“八隅体“都填满了，而如果我们来数一数价电子的总个数，它应该就等于我们这里的二十六。

麻省理工公开课 - 化学原理课程节选

And it is equal to the sum of the number of protons plus the number of neutrons.

它等于质子数,加上中子数。

麻省理工公开课 - 固态化学导论课程节选

And when we talk about angular nodes, the number of angular nodes we have in an orbital is going to be equal to l.

当我们谈到角向节点时，一个轨道的,角向节点数等于ｌ

麻省理工公开课 - 化学原理课程节选

And, that's equal to the product of e the proton number times e.

正等价于,质子数乘以。

麻省理工公开课 - 固态化学导论课程节选