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If I had taken as my interpolation scheme, my white curve here, I could go to infinity and have the equivalent of absolute zero being at infinity, minus infinity.
要注意，如果我们采用，像图中白线这样的插值方案的话,我就可以一直降温下去,相应的绝对零度点。
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A linear interpolation between the two, and then some numbers associated with them, 2 7-1/2 and 22-1/2. Why does he choose 7-1/2 as the freezing point of water?
两者之间做线性插值，一些数值随之标定，7。5和22。5，为什么他选择了7。5作为2,水的冰点呢？
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Something like this. That would be perfectly fine interpolation. All right, we choose to have a linear interpolation.
这种插值的方法也是完全可行的,好，现在我们决定使用，线性插值的方案。
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Because we can take our interpolation here our linear interpolation the slope of this line.
用开尔文,而不是摄氏度作单位。
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The reference points are water freezing or boiling, and the interpolation is linear and then that morphed into the Kelvin scale as we're going to see later.
参考点是水的冰点和沸点,插值是线性的,随后它被发展成为开氏温标,我们之后会看到。
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You can choose a linear interpolation or quadratic, but you've got to choose it.
你可以选择线性插值或抛物线型插值,但你总要做出选择。
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Now there many ways I can connect these two points together. The simplest way is to draw a straight line. It's called the linear interpolation. My line is not so straight, right here. You could do a different kind of line.
最简单的办法是,像这样画一条直线,这叫线性插值,不过我的这条线画得不太直，你也可以用别的办法,比如一条抛物线。
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So the concept of an absolute zero, a temperature below which you just can't go, that's directly out of the scheme here, this linear interpolation scheme with these two reference points.
这就是绝对零度，这样，从线性插值的图像出发，我们得到了绝对零度的概念，你永远无法达到,低于绝对零度的状态。
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And then we need an interpolation scale.
然后我们就可以利用。
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And then an interpolation scheme.
然后要做个插值方案。
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We have an interpolation scheme between zero and 273.16 with two values for this quantity, and we have a linear interpolation that defines our temperature scale, our Kelvin temperature scale.
的两个值做线性插值,就得到了开尔文温标,直线的斜率等于水的三相点,也就是这一点处的f的值,再除以273。16，这是这条直线的斜率，这个量，f在三相点处的值。
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