Let me add, let me make it 17 people so we have an odd number, so go and sit in that row.
我再加一个人这样就是奇数17个人,请到那行中
so given that we chose an odd number of people in the row, if exactly one candidate stands and that candidate is the center candidate, then that's an equilibrium.
假若我们选中行的人数为奇数,如果确实只有一个候选人参选且,那个候选人就是在中间,则那是个均衡
The number 3 is an odd number.
是一个奇数。
In either case, I take that value and multiply back by two, if it was even I get back the original number, if it was odd, I'm not going to get back the original number, so I can just check to see if they're the same.
在两种情况中,我都把结果值,再乘以2,如果x是偶数我就,得到了原来的值,如果x是奇数那么就不会得到,原来的值,因此我看看得到的值,和原来的值相等不相等就可以了。
It's eternally an odd number.
它永远是个奇数。
Claire Elise is going to get her own vote plus 1, 2, 3, 4, 5, 6, 7, 8, 8 votes and Beatrice is getting 1, 2, 3, 4, 5, 6, 7, how did I end up with eight, I thought I had an odd number. 1, 2, 3, 4, 5, 6, 7 there must have been an odd number before.
克莱尔·伊莉斯将获得自己的选票加上,12345678 8张选票,而比阿特丽斯获得1234567,我怎么数出8个来的,我想应该是个奇数,1234567,之前也应该是个奇数
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