• Let me add, let me make it 17 people so we have an odd number, so go and sit in that row.

    我再加一个人这样就是奇数17个人,请到那行中

    耶鲁公开课 - 博弈论课程节选

  • so given that we chose an odd number of people in the row, if exactly one candidate stands and that candidate is the center candidate, then that's an equilibrium.

    假若我们选中行的人数为奇数,如果确实只有一个候选人参选且,那个候选人就是在中间,则那是个均衡

    耶鲁公开课 - 博弈论课程节选

  • The number 3 is an odd number.

    是一个奇数。

    耶鲁公开课 - 死亡课程节选

  • In either case, I take that value and multiply back by two, if it was even I get back the original number, if it was odd, I'm not going to get back the original number, so I can just check to see if they're the same.

    在两种情况中,我都把结果值,再乘以2,如果x是偶数我就,得到了原来的值,如果x是奇数那么就不会得到,原来的值,因此我看看得到的值,和原来的值相等不相等就可以了。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • It's eternally an odd number.

    它永远是个奇数。

    耶鲁公开课 - 死亡课程节选

  • Claire Elise is going to get her own vote plus 1, 2, 3, 4, 5, 6, 7, 8, 8 votes and Beatrice is getting 1, 2, 3, 4, 5, 6, 7, how did I end up with eight, I thought I had an odd number. 1, 2, 3, 4, 5, 6, 7 there must have been an odd number before.

    克莱尔·伊莉斯将获得自己的选票加上,12345678 8张选票,而比阿特丽斯获得1234567,我怎么数出8个来的,我想应该是个奇数,1234567,之前也应该是个奇数

    耶鲁公开课 - 博弈论课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定