Situation number two is I take the same number, and I make a row. They are all in one row.
状态二我将采用同样的数字,并且我做了一个箭头,它们全部都在一列上。
so given that we chose an odd number of people in the row, if exactly one candidate stands and that candidate is the center candidate, then that's an equilibrium.
假若我们选中行的人数为奇数,如果确实只有一个候选人参选且,那个候选人就是在中间,则那是个均衡
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