And we plug in our values and end up with mv squared mv^2/r-Ze^2/ over r minus Ze squared over And I am going to call this equation two.

我们最后的结果,就是,我把这称为方程式二。

麻省理工公开课 - 固态化学导论课程节选

So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.

这里不再等于-z的平方，现在我们等于-有效的z的平方,乘以RH除以n的平方。

麻省理工公开课 - 化学原理课程节选

I know the energy in this first pair would equal -e^2 That is just going to equal minus e squared over 4 pi epsilon zero r naught.

我们明白第一对的能量将会等于,等于,/4πε0，R圈。

麻省理工公开课 - 固态化学导论课程节选

We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.

我们知道如何算出,这个轨道的能级，而且我们知道如何,用这个公式,算出能量，也即是结合能，等于，我们把n等于1代进来，所以除以1的平方，这就是能量。

麻省理工公开课 - 化学原理课程节选

So, the number of nuclei, 119 if we were to sit and count these as well, is 119. So, we'll multiply that by just pi, r squared, to get that cross-section, and divide all of that by 1 . 39 meters squared.

如果你们数的话，原子核的数是，我们用它乘以πr的平方，得到横截面积，除以1。39平方米。

麻省理工公开课 - 化学原理课程节选