So if we want to solve for ionization energy, we can just rearrange this equation.
因此,要想解出电离能,我们只需要将这个方程中的项变换一下位置。
And maybe I can rearrange the furniture a little bit.
也许我可以重新布置一下家具的位置。
So the correct answer for titanium plus two Ar3d2 is going to be argon 3 d 2, whereas if we did not rearrange our order here 4s2 we might have been tempted to write as 4 s 2 so keep that in mind when you're doing the positive ions of corresponding atoms.
所以正2价钛离子,的正确答案是,然而如果我们不重新安排顺序,我们可能会写出2,所以请记住,它当你们在解关于原子,的正离子的时候。
So the point is, once you're at equilibrium none of the other states they're accessible, the system could rearrange itself to form them, but there is no accessible state that has higher entropy than the equilibrium state.
所以要点在于,如果你处于平衡态,其他所有的态都无法达到,我们可以重组体统来形成这些态,但没有一个可以达到的态,有比平衡态大的熵。
You rearrange the parts, the thing changes.
你重新安排这些部分,它就改变了。
We can just rewrite that, if I divide through by 2 and rearrange, it's going to tell me that ?1, or if you like, ?1 is equal to 1 plus B S2.
我们这么写,如果我除以2然后整理,可以得出?1等于1+B*S2
We can also talk about it in terms of if we want to solve, if we, for example, we want to find out what that initial energy was, we can just rearrange our equation, or we can look at this here where the initial energy is equal to kinetic energy plus the work function.
初始能量是多少,也可以,写成另一种形式,我们可以把方程变形,或者我们看这里,初始能量等于,动能加功函数。
So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.
我们可以发现有效的z等于n的平凡,乘以电离能除以里德堡常数,这些所有再开方,所以等于n乘以,除以RH整体的平方根。
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