• I threw away all strategies that were never a best response, then I looked at the strategies that were left.

    我剔除了非最佳对策的策略,然后我看看还剩下哪些策略

    耶鲁公开课 - 博弈论课程节选

  • So are there strategies here that are never a best response to anything?

    这些策略都不会成为最佳对策吗

    耶鲁公开课 - 博弈论课程节选

  • I said those strategies that were a best response to things that have now been thrown away, but not best response otherwise, I can throw those away too.

    这些策略是已被我们的剔除策略的,最佳对策,但仍不是最佳对策,我就剔除它们

    耶鲁公开课 - 博弈论课程节选

  • So let's actually, you might want to be a little bit gentle in your own notebook, but on my board let's get rid of all these strategies that are never a best response.

    所以我们干脆点,在笔记本上,你们动作轻点,我直接在划掉这些非最佳对策的策略

    耶鲁公开课 - 博弈论课程节选

  • We learned that in this game deleting strategies that are never best response, and then deleting strategies that are never best response to anything that is a best response and so on and so forth, yielded a single strategy for each player.

    我们学到了在剔除,非最佳对策的策略后,要再剔除那些在对手最佳对策下,不是最佳对策的策略,以此类推,最后每个参与人都只有一个策略了

    耶鲁公开课 - 博弈论课程节选

  • Once I deleted all the strategies that were never a best response and just focused on that little box of strategies that survived, the picture looked exactly the same as it did before, albeit it blown up and the numbers changed.

    一旦剔除了非最佳对策的策略,仔细研究剩下的策略时,图像还和以前看起来是一样的,尽管坐标改变了,图像放大了

    耶鲁公开课 - 博弈论课程节选

  • So the strategies below 1 and above 2 are never a best response for Player I.

    也就是说小于1及大于2的策略,都不是参与人I的最佳对策

    耶鲁公开课 - 博弈论课程节选

  • So these strategies down here less than 1 are never a best response for Player I.

    参与人I的小于1的策略,永远都不会成为最佳对策的

    耶鲁公开课 - 博弈论课程节选

  • Put another way, what strategies of Player I's are ever a best response?

    换句话说,参与人I的哪些策略,永远不会成为最佳对策

    耶鲁公开课 - 博弈论课程节选

  • And the strategies above 2 were never a best response for Player II.

    大于2的也不是参与人II的最佳对策

    耶鲁公开课 - 博弈论课程节选

  • If Player II chooses 4, then the synergy leads Player I to raise his best response all the way up to 2, but these strategies up here above 2 are never a best response for Player I. Is that right?

    如果参与人II选4,协同导致,参与人I的最佳对策变成2,参与人I的那些大于2的策略,也永远不会成为最佳对策,对不对

    耶鲁公开课 - 博弈论课程节选

  • Similarly, for Player II, the lowest Player I could ever do, is choose 0, in which case Player II would want to choose 1, so the strategies below 1 are never a best response for Player II.

    同理,参与人I最低只能选0,此时参与人II应该会选1,小于1的策略不是参与人I的最佳对策

    耶鲁公开课 - 博弈论课程节选

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