So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.

这里不再等于-z的平方，现在我们等于-有效的z的平方,乘以RH除以n的平方。

麻省理工公开课 - 化学原理课程节选

And that's going to be equal to negative z effective squared times r h over n squared.

有效的z的平方,乘以RH除以n的平方。

麻省理工公开课 - 化学原理课程节选

So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.

我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。

麻省理工公开课 - 化学原理课程节选

We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.

我们知道如何算出,这个轨道的能级，而且我们知道如何,用这个公式,算出能量，也即是结合能，等于，我们把n等于1代进来，所以除以1的平方，这就是能量。

麻省理工公开课 - 化学原理课程节选

So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.

我们可以发现有效的z等于n的平凡，乘以电离能除以里德堡常数,这些所有再开方，所以等于n乘以,除以RH整体的平方根。

麻省理工公开课 - 化学原理课程节选