It has to be,I think,in way, reciprocal and symmetric."
VOA: standard.2009.11.16
The second way to have something that is net nonpolar is to have spatially symmetric disposition of polar bonds.
第二种构成,需要空间非极性,就是需要极性键的空间对称分布。
Even though the best response is pretty complicated-- and by the way, obviously the things are symmetric for Payer II.
虽然最佳对策是很复杂的,顺便说一下 选手2的情况也明显是这样
You have a symmetric molecule, and let's see.
一个非常对称的分子,再看看。
Also, it is cylindrically symmetric around the bonding axis, so this is how we know that it's a sigma orbital.
此外,它关于键轴是圆柱对称的,这就是为什么我们知道它是sigma轨道。
That's an example of symmetric sequence and it happens that most restriction enzymes also recognize those spaces.
这是一个对称序列的例子,大多数限制性内切酶都能识别这些序列
And, I know I need to come up with four symmetric equi-length bonds, and let's just see, let's draw the structure here.
我想我们需要,4个对称的等长的键,让我们画出CH4的结构。
Now, it's not going to be symmetric is it, because there's two fluorines and two chlorines.
现在,它将不会对称,因为有两个氟原子和两个氯原子。
If I now hybridize these, if I take these and I make four symmetric, now, these are just the sp3 orbitals.
如果我将他们杂化,然后形成4个对称的轨道,这就是sp3轨道。
So, somehow we have to figure out a way to take orbitals that are non-symmetric, and convert them into orbitals that are symmetric.
所以有时我们需要找到一个方法,让不对称的轨道,转变为对称的轨道。
Same bond, symmetric bonds means equal energy, which means equal links.
相同的对称的化学键意味着相等的能量,相同的联系。
Just to point out in passing, up to now, we've been looking mostly at symmetric games.
顺便说一下,到目前为止,我们所学的大部分是对称博弈
And let's also make our egg perfectly symmetric and perfectly round.
而且我们要把蛋想成是,完全对称完全圆的。
We somehow have to take hydrogen, attach it to carbon, and we have to make it symmetric, and we have to make it nonpolar.
我们需要把H接到C周围,而且我们需要让它是对称,且非极性的。
And yet, the molecule is symmetric and nonpolar.
所以这个分子是对称非极性的。
Notice this game is not symmetric in the payoffs or in the strategies.
但注意此博弈的策略与收益是非对称的
There's no particular reason why games have to be symmetric.
博弈未必都是对称的
If it's symmetric, that means that each bond has exactly the same energy.
这意味着如果他们对称,那么每根键的能量是一样的。
Symmetric disposition of polar bonds still results in a nonpolar molecule.
空间对称的极性键分布,还是会导致整个分子为非极性分子。
If we can do that, we'll end up with a symmetric nonpolar molecule.
如果我们能这样做,我们就能得到那些对称非极性的分子。
But, we also know that it's symmetric.
而且非常对称。
And, it's going to be symmetric.
现在是对称的了。
Right, it's symmetric.
是的,对称。
Can everyone see that is symmetric?
每个人都可以看出这他们是对称的
It's perfectly symmetric.
它是完全对称的。
The thing is still not dominated and we could still have done exactly the same analysis, and actually you can see I'm not very far off in the numbers I made up, but things are not perfectly symmetric.
这虽然不能成为劣势策略,但我们还是能得出一样的分析结果,实际上这和我编的数字相差也不是很远,凡事并不总是绝对对称的嘛
Player II has three choices, this game is not symmetric, so they have different number of choices, that's fine.
参与人II有三种选择,这个博弈不是对称的,所以他们可选策略数量不同,这无所谓
This bond is polar, but again, as I alluded to earlier, because the carbon is centered in the tetrahedron, because of the sp3 hybridization, the molecule itself is symmetric and nonpolar.
这个键是非极性的,但是,我们断言过早,因为C是中心原子,由于sp3杂化,这个分子本身是非极性的且对称的。
It makes sense to draw the wave function as a circle, because we do know that 1 s orbitals are spherically symmetric.
把波函数画成一个圆是有道理的,因为我们知道1s轨道是球对称的。
This is the effort cost. Similarly, player II, everything's symmetric here Player II's payoff is the same thing.
这是她的努力成本,由对称可得,参与人II的收益是一样的
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