What I am going to do now is I am going to multiply by N Avogadro and then add Born repulsion.

我接下来要做的是,将其乘以阿伏加德罗常数,再加入Born的排斥作用。

麻省理工公开课 - 固态化学导论课程节选

But remember that we need to multiply it by the volume here, the volume of some sphere we've defined.

但记住我们需要把它乘以体积，乘以一个我们定义的壳层的体积。

麻省理工公开课 - 化学原理课程节选

I am only counting in one direction, 2 so I have to multiply this whole thing by two because I have to count both directions.

因为我只是在一个方向上计数，所以我要把这些所有乘以,因为我们必须考虑到2个方向。

麻省理工公开课 - 固态化学导论课程节选

Multiply a by a to the b minus 1.

这很不错对不对？

麻省理工公开课 - 计算机科学及编程导论课程节选

Can I multiply the ? by the 4 just to save myself some time?

我先算?乘以4吧,这样省事儿

耶鲁公开课 - 博弈论课程节选

And then for some reason, that nobody understands, 16/15 he decided to multiply again by 16/15, and that's how we get 32 for freezing of water and 96 in his words for the temperature in the mouth or underneath armpit of a living man in good health.

然后，因为同样的原因，没人搞得明白，他决定再乘以，现在水的冰点变成了32度,而96度，拿他的话来说,是健康状况良好的人,口腔或腋窝的温度。

麻省理工公开课 - 热力学与动力学课程节选

Then you're able to generalize that and say, if you multiply it by 2.6, I mean a vector 2.6 as long as A.

然后可以将其推广到更一般的情况,如果用2.6乘以它,所得矢量即为矢量 A 的2.6倍

耶鲁公开课 - 基础物理课程节选

So, once we figure out what our probability of backscattering is, we'll just raise that to the 1/2, and we'll multiply that by 12 . 20 centimeters.

所以一旦我们,知道了散射概率，我们开根号。

麻省理工公开课 - 化学原理课程节选

So if we take this term, which is a volume term, and multiply it by probability over volume, what we're going to end up with is an actual probability of finding our electron at that distance, r, from the nucleus.

如果我们取这项，也就是体积项然后，乘以概率除以体积，我们能得到的就是真正在距离,原子核ｒ处找到电子的概率。

麻省理工公开课 - 化学原理课程节选

What Einstein then clarified for us was that we could also be talking about energies, and he described the relationship between frequency and energy that they're proportional, if you want to know the energy, you just multiply the frequency by Planck's constant.

爱因斯坦阐述的是我们,也可以从能量的角度来谈论，他描述频率和能量之间的关系,是成比例的，如果希望知道能量值，你用普朗克常数乘以频率就可以了。

麻省理工公开课 - 化学原理课程节选

Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.

等式两边同时乘以2,得到,2q1*=/b-q1

耶鲁公开课 - 博弈论课程节选

So, the number of nuclei, 119 if we were to sit and count these as well, is 119. So, we'll multiply that by just pi, r squared, to get that cross-section, and divide all of that by 1 . 39 meters squared.

如果你们数的话，原子核的数是，我们用它乘以πr的平方，得到横截面积，除以1。39平方米。

麻省理工公开课 - 化学原理课程节选