• It literally halves the amount of time it takes to solve that problem but we can actually do better.

    它能把解决问题时间的缩短一半,但其实我们能做的更好。

    哈佛公开课 - 计算机科学课程节选

  • I'm gonna ask you to find resources that help inform your opinions about how we can do a better job of building a better learning community.

    你们要搜索资料,以便于阐述关于,如何更好地,构建学习社群的观点。

    麻省理工公开课 - 媒体、教育、市场课程节选

  • Are there resources that we can go to to help us do this work better?

    您能否告诉我们一些我们能寻找到并帮助我们,将这件工作做得更好的资源?

    普林斯顿公开课 - 人性课程节选

  • And so this begs the question, even in the context of these cups, how can we possibly do better if at the end of the day in order to figure out if two cups or if two people or if two ints inside of an array are bigger or smaller than one another it feels like we have to do this comparison work anyway.

    这样就回避了问题的实质,从这些杯子的相互关系来看,我们怎样才能更有效地,找出序列中比其他元素,都大或都小的两个杯子,两个人,两个数,看起来我们无论如何都得,做比较的工作。

    哈佛公开课 - 计算机科学课程节选

  • But luckily, we can do a little bit better than that.

    幸好我们还可以做更深入的研究

    耶鲁公开课 - 博弈论课程节选

  • But we can do better than that.

    但我们可以想出更好的解释。

    耶鲁公开课 - 弥尔顿课程节选

  • Depending on where the assets expected returns are and the assets' standard deviations, we can see that we might be able to do better than--have a lower variance than either asset.

    根据资产的预期收益,以及收益的标准差,可以看到我们有更好的选择,这里的方差值比以上两种方案都要低。

    耶鲁公开课 - 金融市场课程节选

  • We can do better.

    我们能做得更好。

    麻省理工公开课 - 固态化学导论课程节选

  • If we can sort things, you know, we get this n log n behavior, and we got a n log n behavior overall. But can we actually do better in terms of searching.

    如果我们可以排序,如你所知,我们有n,log,n级别的算法,并且我有一个整体的n,log,n级别的算法,但是我们在搜索方面可以做的更好吗?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So, in fact, it is true, it is in fact true, so we can conclude that 2 dominates in fact, we can do a bit better than that we can say strictly dominates 1.

    事实的确如此,我们可以得出结论立场2优于立场1,或者更进一步说,立场2严格的优于立场1

    耶鲁公开课 - 博弈论课程节选

  • Actually, we can do it a little better than that, since we know the game is symmetric, we know that S1* is actually equal to S2*.

    实际上我们能得出更多,因为我们知道这个博弈是对称的,我们知道S1*=S2

    耶鲁公开课 - 博弈论课程节选

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