• So z equals 7 -- this is the cut-off where, in fact, the sigma orbital is going to be higher in energy than the pi 2 p orbitals.

    所以z等于7-这是分界点,实际上,sigma轨道能量,要比π2p轨道高。

    麻省理工公开课 - 化学原理课程节选

  • z And what you need to remember is if the z 8 is equal to eight or greater, such as oxygen being the cut-off point, this sigma 2 p orbital is actually lower in energy than the pi 2 p orbitals, the molecular orbitals.

    你们要记住如果,等于或者大于,就像O是分界点,这时sigma2p轨道,比π2p轨道能量更低。

    麻省理工公开课 - 化学原理课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定