And it turns out that if we have a, for example, for s, a very large z effective or larger z effective than for 2 p, and we plug in a large value here in the numerator, that means we're going to end up with a very large negative number.

结果是如果我们有一个，举例来说对于s一个很大的有效电荷量或者,比2p大的有效电荷量，并且我们将一个较大的值代入计算器，那意味着我们最后会得到,一个非常大的负数。

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