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It implies that this algorithm is calling itself again and again, and again, and on each time the size of the problem I'm trying to sort is being divided by what?
这就说明此算法会一次又一次地调用自己,每次我要排序的问题规模大小,会除以多少呢？
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In fact, there are some very old books that show this as the average, the sum divided by two arithmetic mean, but the modern practice is to use the geometric mean.
事实上，一些很老的书籍上,平均的定义就是算数意义的，总的来说被分为两种算数意义，但现代我们多用几何意义。
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And the relationship that he put forth is that the momentum is equal to Planck's constant times nu divided by the speed of light, or it's often more useful for us to think about it in terms of wavelength.
爱因斯坦提出的关系式是,动量等于普朗克常数,乘以υ除以光速，或者用波长来表示,通常更容易让我们想明白。
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What's 17 divided by 3 is roughly -- one point something, so one point dot, dot, dot, right?
7除以3大概是多少呢--1点几，所以是1点几，几，几，是不？
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All that matters is the ratio: how many shares I own divided by the number of shares outstanding.
比例才是最根本的要素,我有的股数除以总发行股数
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So, three divided by five is zero, with a remainder of three.
因此，3除以5等于，余数为3。
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That is 6 Newtons divided by 3 kg is also an acceleration of 2.
即,6 牛除以 3 千克同样得到加速度是 2
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which is f , divided by the value of the x-axis here.
斜率，而f是p趋于0时pV的极限。
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b The repulsive term goes as some constant lower case b divided by R to the n. N is not the quantum number.
这种斥力很想一个固定的小写字母,被R到n分开的话，N不是量子数。
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Just take a look: if this is 9, 5 divided by 9 is always going to be 0 point something, and if you thus have two integers and you're rounding down, which is what happens when you do integral math we're using this operator, I'm going to get zero times whatever.
稍微看一看：如果这是9，5除以9会得到,0点几，如果你用两个整型数,你舍去小数，这就是当你们,用整型数使用这个操作的所发生的事情，我将得到数值0乘以任何一个数字。
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Alright. So, since we have these terms defined, we know the frequency and the wavelength, it turns out we can also think about the speed of the wave, and specifically of a light wave, and speed and is just equal to the distance that's traveled divided by the time the elapsed.
好了，我们已经定义了，这些术语，我们知道了，频率和波长，现在可以来考虑,波的速度了，特别是光波的速度，速度等于它走过的距离,除以所用的时间，因为我们。
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If you have an interest rate--this is approximately equal to-- one plus the real interest rate is equal to divided by one plus the rate of inflation.
如果你知道名义利率,那实际利率约等于,这里应该是=,/
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So now we have that energy is equal to the negative of the Rydberg constant divided by n squared.
我们可以把能量方程大大简化,现在能量等于负的Rydberg常数除以n平方。
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And since we are not expecting the mass of the particle to change, what we really are saying is the uncertainty in its velocity times the uncertainty in its position is greater than the ratio of the Planck constant divided by 2 pi.
因为我们不期望,粒子质量发生变化，我们说的是,它速度的不确定度,乘以它位置的不确定度,比普朗克常量,除以2除以圆周率要大。
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Three divided by five is zero?
除以5等于0么？
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Therefore, it'll compress by an unknown x, which is equal to mg divided by the force constant of the spring.
因此它的压缩量为 x,也就等于 mg 除以弹簧的弹性系数
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Again, this is price divided by ten-year earnings, not one-year earnings.
这是价格除十年的收益,不是一年的
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But in our case, the probability of backscattering is going to be the number of balls that backscatter, and that's going to be divided by the total number of ping-pong balls.
用20除以132000，但现在背散射,的概率是被散射回来的小球，除以总的小球数,你们记得。
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Just to give you a sense of what that means, if the 264 figure is pure covalency and the 344 is partial ionic character, what fraction of the 608 is 344? 344, which is partial ionic character, 57% divided by 608 times 100 is 57%.
它只是给你一个这样的概念，264千焦每摩是完全共价成分的键能,而344是离子成分的，344除以608是多少，344，是不完全的离子特性，除以608乘以100得到。
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V All right, or p is equal to a constant divided by volume.
或者p等于常数C除以。
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n It takes discrete values, multiples of some integer n, and the multiplication factor is the ratio of the Planck constant divided by 2 pi where n takes one, two, three and so on.
这些离散的值乘以整数，乘积因子,是普朗克常数除以2π,其中n可以取1，2，3，等等。
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The real interest rate, computed from nominal rates, is equal to one plus the nominal rate divided by one plus the inflation rate, so it corrects for inflation.
由名义利率算得的实际利率 等于,/,它是一个经通胀调整后指标
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Cp And delta T is given by the heat, which has to do with how much of the candle burnt, divided by the constant pressure heat capacity.
T等于热量q除以恒定的等压热容，其中热量与，蜡烛燃烧的多少相关。
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So, since the speed of light equals lambda nu, we can say that momentum is equal to h divided by lambda.
所以，既然光速等于λ乘以υ,我们可以得到动量等于h除以λ
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Their difference divided by the difference in times is going to be the acceleration.
它们的差值再除以时间的差值,就是加速度
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3 So here what I'm doing is 17 divided by 13, but because of this parenthetical, , -- because of that parenthetical -- that has nothing to do with math; -- this is a programming language thing -- that is a casting operation.
所以这里我要做的是用17除以，但因为这样的题外话，因为那样的题外话-,还是没有做完这个数学题;,这是一个编程语言的东西-,那是一个计算操作。
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The 5 is going to get divided by 9 first.
先做5除以。
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If x was even, x divided by two is going to be actually the half of x, right?
如果x是偶数的话，x除以2当然,就等于x的一半了，对不对？
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e The charge on the anion times minus e, so there is the minus e squared, 0R0 and divided by 4 pi epsilon zero r naught, because now I am evaluating this function at r naught, one minus one over n where n is the Born exponent.
阴离子的电荷乘以，因此会有-e的频繁，除以4πε,因为现在我用r圈评估这个函数，1-1/n，n是波恩指数。
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