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Now that already tells us what we know, which is that the efficiency is going to be something less than zero, right?
我们都知道这个，这结果就是说效率,是负的，对吗？
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Anything else, which is to say any spontaneous process, it'll be less than zero.
其它任何情况下，也就是任何自发过程，都将小于零。
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And, if this quantity is less than zero, the bonding is favorable.
如果这个数小于，能够形成键。
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If n is greater than zero, I decided I would say, "You picked a positive number, backslash n," so put the cursor on the next line, else if n was not less than zero, I say, "You picked a negative number, backslash n."
如果n比0大，我就决定来说：,“你选择了一个整数，反斜杠n“，所以你把光标,放在下一行，另外如果n不小于0，我说：,“你选择一个负数，反斜杠n“
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The total work is less than zero.
说明系统对外界做功。
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du external dV minus T surroundings dS is less than zero.
加上压强p，du，plus，p,乘以dV减去环境温度T乘以dS小于零。
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I can write this as d less than zero.
我可以把这个写成的d小于零。
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So we immediately get du at constant S and V is less than zero.
这样我们马上就得到以下结论：,在等熵，等容条件下dU必须小于零。
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So, du plus p dV is less than zero.
因此，du加上pdV需要小于零。
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So all that's left is negative T dS is less than zero.
只剩下TdS小于零。
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So if you had a high temperature, this a small compared to b. If you're negative which means that dT/dp at constant H is less than zero.
高于反转温度，这一项相比于b很小,意味着H恒定时,偏T偏p小于零。
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So we could write that criterion as dH less than zero.
我们可以认为dH小于零即为我们的判据。
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It means du is less than zero.
这意味着du小于零。
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So in this experiment here, delta p is less than zero. You need to have this whole thing greater than zero. So delta T is less than zero as well. So if you're below the inversion temperature and you do the Joule-Thomson experiment, you're going to end up with something that's colder on this side than that side.
所以在这个实验中，Δp小于零,这全部都大于零,因此ΔT也小于零,所以如果在低于转变,温度的情况下做焦耳-汤姆孙实验,最后的结果是,这边的温度比这边低。
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If T is less than T inversion, you have the opposite case, and dT/dp is greater than zero.
如果T比转变温度低,情况就相反，偏T偏p大于零。
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We discovered that the quantity dA, under conditions of constant volume and temperature, dA TS And A is u minus TS.
我们发现在恒定的体积和温度下，亥姆赫兹自由能的变化，小于零，is，less，than，zero。,亥姆赫兹自由能A等于内能u减去。
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Going around in a cycle the integral of dq over T is less than or equal to zero.
对一个循环过程作dq除以T的积分,小于等于零。
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It's gonna be zero if N is less than 2, right.
如果N小于2，T应该是。
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