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It is joules per atom. Or, if you multiply by Avogadro's number then you will get joules per mole.
焦耳每个原子，或者，如果乘以,阿伏伽德罗常数你会得到焦耳数每摩尔。
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On the contrary, God explicitly commands humans to be fruitful and multiply, and he does that in the P-source, right?
相反地，上帝曾明确要求人类,开枝散叶人丁兴旺，而这属于不洁的范畴，不是吗？
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475 Multiply by 1.7475 787kJ/mol and you end up with minus 787 kilojoules per mole.
乘以1。,最终得到。
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But remember that we need to multiply it by the volume here, the volume of some sphere we've defined.
但记住我们需要把它乘以体积，乘以一个我们定义的壳层的体积。
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You've got to juggle the two equations, multiply that by 4, multiply that by 3, add and subtract and so on.
同时处理这两个方程,这个两边乘以4,另一个两边乘以3,将两方程相加或相减求出答案
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Well, Fahrenheit came along and thought, well, you know, 7-1/2, that's kind of silly; 22-1/2 that's, kind of silly So let's multiply everything by four.
然后华伦海特来了，他想，7。5，听起来有些犯傻;,22。5，那也够傻的,我们还是把所有的东西乘以四吧。
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OK, I can certainly print out strings, but I can actually add strings together, and just as you saw, I can multiply strings, you can kind of guess what this is going to do.
当然我可以显示字符串，但是其实我还可以令字符串相加，如你所见到的，我可以令字符串相乘，你们可以想想答案是什么。
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You don't have to count all the leaves on the tree, you can take a sample and you count that and then you multiply.
你不必数树上所有的叶子,你可以抽样,然后计数,再相乘即可
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Can I multiply the ? by the 4 just to save myself some time?
我先算?乘以4吧,这样省事儿
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Take your own weight in your mind and multiply it by three.
想一下你们自己的体重,然后再乘以三
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And so we might need to work out various, more complicated, formulas here, where we multiply the pain times its duration and take into account its intensity, get the sheer quantity of pain that way.
我们需要编制出各种，更复杂的公式，以便增加痛苦的倍数，延续时间,还要考虑痛苦的强度，获得痛苦的纯量。
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If you multiply her, then you want to have as much depth to fill in behind to close that hole as you can, so that that would make your phalanx more sturdy, because you could take more casualties without breaking, that seems reasonable to me.
如果再多一些,你就需要在后面增加足够的排数,尽可能地填补缺口,这会使你的方阵固若金汤,即使伤亡惨重也不影响阵容的坚固,这在我看来是合理的
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No, instead we have to click other amount at bottom right there, when we have to input 4-0-0 in this screen 4-0-0 after consulting visually the little cheat sheet on the device itself it tells you in a very long chart how much one pass costs so we multiply and type in 4-0-0, we hit enter.
不，然而我们必须点击,右下边的这个，当我们需要在这个屏幕上,输入0,通过咨询那个设备上小说明,它在一个很长的图表上,告诉你，每一站需要多少钱，我们加起来,输入了4-0-0，点击输入。
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So, once we figure out what our probability of backscattering is, we'll just raise that to the 1/2, and we'll multiply that by 12 . 20 centimeters.
所以一旦我们,知道了散射概率，我们开根号。
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But I know when I multiply a vector by a number, I get a vector in the same direction.
但是我所知道的是当矢量乘以一个常数,我会得到一个同方向的矢量
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So if we want to talk about the volume of that, we just talk about the surface area, which is 4 pi r squared, and we multiply that by the thickness d r.
如果我们要讨论它的体积，我们要用的是表面面积，也就是４πｒ的平方，乘以厚度ｄｒ
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Because like Adam and Eve in the first creation story, Noah is told to be fruitful and multiply.
因为就像第一个创世纪中的亚当和夏娃，诺亚被命令多子多孙。
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Subtract that from one, 100 multiply it by 100 and you have something between zero and 100.
用一减去后面那部分，再整体乘以,你就能得到0-100间的一些数值。
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I am only counting in one direction, 2 so I have to multiply this whole thing by two because I have to count both directions.
因为我只是在一个方向上计数，所以我要把这些所有乘以,因为我们必须考虑到2个方向。
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Multiply a by a to the b minus 1.
这很不错对不对？
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How do we do that correction? When I first tried this, I thought, fine I'll multiply by 365/60, but I forgot this is a leap year.
那么怎么换算呢,我第一次试的时候,我想,我乘以365/60,但是我忘了,今年是闰年
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I want you to be fruitful and multiply, and so on.
我希望你们丰收多产，等等。
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And then for some reason, that nobody understands, 16/15 he decided to multiply again by 16/15, and that's how we get 32 for freezing of water and 96 in his words for the temperature in the mouth or underneath armpit of a living man in good health.
然后，因为同样的原因，没人搞得明白，他决定再乘以，现在水的冰点变成了32度,而96度，拿他的话来说,是健康状况良好的人,口腔或腋窝的温度。
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I can't multiply while I'm standing up.
我站着的时候就算不清乘法了
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That's true, but especially because of my parenthesization 32 over here, because I'm saying, "Do f minus 32, but then multiply it by the division on the left."
是那样的，但是特别地，因为我这里加上了括号,因为我指明，“f减去，然后它乘以左边的那个除法的结果“
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a perfectly spherical shell dr at some distance, thickness, d r, dr we talk about it as 4 pi r squared d r, so we just multiply that by the probability density.
在某个地方的完美球型壳层,厚度，我们把它叫做4πr平方，我们仅仅是把它,乘以概率密度。
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And what I am going to do is say start with this ion, add up the energy associated with the interactions between that ion and everybody else in the row and then multiply it by Avogadro's number, because that is the number of atoms there are in a row.
接下来我要从这一离子开始，加上相互作用的能量，也就是这一离子,和其它所有在这一行的离子之间的能量,再乘以阿伏加德罗常数，因为这是在一行的原子的数量。
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Once you've got that, you can do minus 7 times a vector Just take the vector, multiply it by Pi and flip it over.
明白这点之后,你就可以计算-7乘以矢量,只需用 π 去乘以那个矢量,然后将其方向调转
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If I multiply these two, what is the coulomb times a volt?
如果我把这两个乘起来，库仑乘以伏特是多少？
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