• So, in order to fill our octet, what we do is put two on the nitrogen and two on the carbon.

    因此,为了填满我们的“八隅体“,我们需要将两个放到氮上,将另外两个放到碳上。

    麻省理工公开课 - 化学原理课程节选

  • So what we can actually directly compare is the dissociation energy or the bond strength of nitrogen versus hydrogen.

    因此实际上我们可以直接进行比较,对氮分子与氢分子的离解能,或键的强度。

    麻省理工公开课 - 化学原理课程节选

  • It doesn't go all the way to absolutely 100 percent ammoniazero hydrogen zero nitrogen if they were mixed together with the right ratios.

    即使按适当比例混合,也不会出现全部氨气,没有氢气和氮气的情况。

    麻省理工公开课 - 热力学与动力学课程节选

  • If we take nitrogen, we've got N2, and we've got one, two, three, four, five.

    比如说氮,我们得到了氮气,我们有一个,两个,三个,四个,五个。

    麻省理工公开课 - 固态化学导论课程节选

  • So, electron promotion does not happen in terms of nitrogen, because it would not increased our number of unpaired electrons.

    这里对于氮原子不会有电子激发,因为这不会增加,未配对电子的数目。

    麻省理工公开课 - 化学原理课程节选

  • We see that the radius is shorter, so that means that the nitrogen-nitrogen bond is going to be shorter.

    我们看到这个距离更短,这就意味着,氮与氮之间的键应该更短。

    麻省理工公开课 - 化学原理课程节选

  • 4 6 Just as in nitrogen, we get two, four, six here, but now we have two more electrons.

    对于氮,我们有,但是现在我们有两个多的电子。

    麻省理工公开课 - 固态化学导论课程节选

  • So this is not going to be a favorable process, we're going to find that the electron affinity is actually a negative 7 kilojoules per mole for nitrogen.

    因此这并不是一个容易发生的过程,我们会发现氮的电子亲和能,应该是负的,7,千焦每摩尔。

    麻省理工公开课 - 化学原理课程节选

  • So, shared electrons are the ones that are shared between the carbon and the nitrogen, so we have 6 shared electrons, and we want to take 1/2 of that.

    共用电子是那些在碳和氮之间,被它们共用的电子,那么我们有六个共用电子,然后我们要给它乘上二分之一。

    麻省理工公开课 - 化学原理课程节选

  • So in terms of nitrogen that starts off with a valence number of 5, again we have 2 lone pair electrons in the nitrogen, and again, we have 6 electrons that are shared.

    对于氮来说,我们应该从五个价电子开始,同样,氮也有两个孤对电子,共用电子的个数也一样,是六个。

    麻省理工公开课 - 化学原理课程节选

  • This is very easy molecule because we know exactly where to put them without even having to think, we only have one option, and we'll make a triple bond between the carbon and the nitrogen.

    这个分子非常简单,因为我们知道应该把它们放在哪里,甚至不用去想,我们只有一个选择,我们将在碳与氮之间形成一个三键。

    麻省理工公开课 - 化学原理课程节选

  • So if we take a look at nitrogen here, what you'll notice is we have thre available for bonding, - and we already have our lone pair -- one of our orbitals is already filled up.

    如果我们看一下氮原子,我们注意到我们可以成3个键,我们已经有一个孤对-,其中的一个轨道已经被填满了。

    麻省理工公开课 - 化学原理课程节选

  • 090 We have 1,090 for carbon, 1000 1,000 for sulfur, 1400 and 1,400 for nitrogen.

    碳的是,硫的是,而氮的是。

    麻省理工公开课 - 化学原理课程节选

  • Here is the atomic nitrogen, here is the atomic nitrogen and these are the orbitals of molecular nitrogen.

    这是氮原子,这是氮原子,然后这是氮气的分子轨道。

    麻省理工公开课 - 固态化学导论课程节选

  • So we can put actually all 4 of our extra electrons in between the carbon and the nitrogen.

    因此我们可以把这剩下的,四个电子都放在碳和氮之间。

    麻省理工公开课 - 化学原理课程节选

  • So, for instance, this would suggest to us by the way it's written that the hydrogen is attached to the nitrogen and not the oxygen.

    因此,比如,这样的写法会提醒我们,这个氢原子是与氮原子成键的,而不是氧。

    麻省理工公开课 - 化学原理课程节选

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