If I had lists of lists of lists, then it would only take out the first level of it.

贴到另外一个数组的后面，它当然是实现了套数组的操作。

麻省理工公开课 - 计算机科学及编程导论课程节选

We'll get to discussing that, but what I want to point out here again is the fact that instead of just being dependent on n, the energy level is dependent on both n and l.

我们将要讨论它，但是我想指出的是事实上能级不只是与n有关,而是与n和l都有关系，而且n不再是。

麻省理工公开课 - 化学原理课程节选

So the question was, why is this return down at this level, it says, well if I ever execute out of this FOR loop, I get to the end of the FOR loop without hitting that branch that took me through the return, then and only then do I want to actually say, gee, I got to this place, there isn't any value to return, none I'm going to return none and none.

问题是，为什么它是在这个级别上返回值呢，意思就是如果我出了这个for循环,就意味着我运行的过程中没有走到任何,带return的支路上去,这时也只有这时我才能说天呐,我终于走到这儿了，这时不会返回任何值，只会返回none和。

麻省理工公开课 - 计算机科学及编程导论课程节选

And when you talk about n for an orbital, it's talking about the shell that shell is kind of what you picture when you think of a classical picture of an atom where you have 1 energy level, the next one is further out, the next one's further away.

当你们谈到，某个轨道的n时，你们说的是壳层，壳层就是,你想象，一个原子,的经典图像时的场景,你有一个能级，下一个再更远的地方，再下一个又更远。

麻省理工公开课 - 化学原理课程节选

So what we'll do is this problem here, which is let's calculate out what the wavelength of radiation n would be emitted from a hydrogen atom if we start at the n equals 3 level and we go down to the n equals 2 level.

我们来做这个问题,让我们来计算一下,从n等于3到,等于2能级氢原子辐射的波长是多少。

麻省理工公开课 - 化学原理课程节选