We want a relationship in p-V space, not in T-V space. So we're going to have to do something about that. But first, it turns out that now we have this R over Cv.
我们想要p-V空间中的结果,而不是T-V空间中的,因此需要做一些变换,先来看现在的关系,它跟R/Cv有关。
On the contrary, God explicitly commands humans to be fruitful and multiply, and he does that in the P-source, right?
相反地,上帝曾明确要求人类,开枝散叶人丁兴旺,而这属于不洁的范畴,不是吗?
And our job is to find out what is the mathematical description of this path, this line in p-V's case that connects these two point.
我们的任务,就是找出,描述这条曲线的方程。
That's why we said on the personality theory,as we went ahead in time, once the P-functioning stops,I don't exist anymore.
这就是为什么根据人格理论的说法,随着时间流逝,人格功能停止,我也不再存在。
It's 109 . 5 is what we would expect for methane because it's tetravalent, but here we're just seeing something that's divalent, and they're both in p orbitals that are perpendicular to each other.
因为甲烷是四价的,我们预测是109。,但这里我们,看到的是二价的,它们都在。
OK, in fact if we look at this, if I say, print of p, it prints it out in that form.
好,实际上如果,我们来看看这个,如果我输入,p的显示。
People make really stupid decisions and so as you know in this course with P sets there are three axes that we look at when evaluating your code.
人们做了一个愚蠢的决定,在这个课程上,通过习题集,当执行你的代码的时候,有三个评估方面。
First of all, they were dying in such numbers; p was so high that it was expensive.
首先,他们死亡的概率如此之大,以至于保费会非常高
And so, if we look at our box notation, we've got three states in the p orbital.
因此,如果我们看看我们的盒子符号,在p轨道有三个状态。
Now we're going to--notice there's no subscript on this P and you'll see why in a second.
我们要,注意这个P没有角标,你们很快会知道这是为什么
Although they will be engaged in P-functioning later on, it's not true right now that they can engage in P-functioning.
虽然他们后来能够有人格功能性,但是现在却没有。
So perhaps in the relevant sense, the person can still engage in P-functioning, so they're not dead. Good enough.
所以也许在相对的条件下,这个人还有人格功能性,他们还没有死,很好。
In Genesis 1. He commands proper care of the dead, and he also does that in the P-source.
在《创世纪》的第一章,他要求合理处置死者,可尸体也是不洁的。
In that case point p 1 doesn't correspond to this point, it actually corresponds to the point of radius 2 and angle 1, which is about here.
基本上也就是说这是第一个点1,这是第二个点,把它们的值加到一起,然后我就得到了目标点,好,这听起来挺不错的。
At this point, we have no other choice but to double up before going to the next energy level, 2px so we'll put a second one in the 2 p x.
在这点上我们没有其他选择,而只有双倍填充,在到下一个能级之前,所以我们放入第二个电子至。
The second problem is, 1 suppose actually I had p 1 and p 2 were in polar form, and I ran add points on them.
第二个点也就是,半径为3角度为1,也就是差不多在这,那么什么点,对不起。
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