The answer is that simply knowing the particle has an acceleration is not enough to tell you where the particle will be.
答案是这样的,仅仅知道质点的加速度,是不足以告诉你它接下来的运动的
This particle is constantly changing its direction, but it therefore has an acceleration and the acceleration, we have shown here, is pointing towards the center.
这个质点恒定地改变它的运动方向,因此它具有加速度,而且这个加速度,我们前面也讲过了,指向圆心
I want to consider a particle which has definite acceleration a, a constant one, but a is now a vector.
我想考虑一个加速度为 a 的质点,加速度恒定,但 a 是一个矢量
When a particle moves in a circle, it has an acceleration towards the center of this size, v^2 over R.
当一个质点在圆周上运动时,它有一个指向圆心的加速度,v^2 / R
You're only given the particle has acceleration a, and you are asked to find out what is x?
你只知道质点的加速度为a,你需要求出x是多少
So what I'm saying here is we are specializing to a limited class of motion where the particle has a definite acceleration, a.
我在这里想说的是,我们正在专门讨论一类问题,这些问题中,质点都有一个确定的加速度a
You can easily check by taking two derivatives that this particle does have the acceleration a.
你可以很容易地通过求两次导来验证,这个质点的加速度确实为 a
It tells you when a particle moves in a circle, it has an acceleration in a negative R direction, namely directed towards the center.
它告诉你当一个物体在圆周上运动时,它有一个在 -R 方向的加速度,也就是说是直接指向圆心的
So, this is the most general position for a particle of constant acceleration, a.
这是一个加速度为a的匀加速质点,位移的最一般的表达式
We said, "Let's take, for the simplest case that we can possibly imagine, namely a particle moving in one dimension along the x-axis with a constant acceleration a.
我们说过,"考虑我们可以想象的最简单的情况,即质点在一维空间运动,沿着 x 轴且保持恒定加速度 a
Whenever you see a particle moving in a circle, even if it's at a constant speed, it has an acceleration, v square over r directed towards the center.
只要看到质点做圆周运动,即使是匀速圆周运动,也存在一个加速度,大小为 v^2 / r,方向指向圆心
So, this certainly describes a particle whose acceleration is a.
它确实描述了一个加速度为a的质点的运动
So, the question we are going to ask is the following, "If I tell you that a particle has a constant acceleration a, can you tell me what the position x is?"
接下来要问的问题就是,如果我说某质点加速度恒为a,你能告诉我它的位移x是多少吗
Conversely, if you get an answer and it doesn't seem to make sense, then you've got to go back and ask, am I violating some of the assumptions, and here you will find the assumption that the particle had that acceleration a is true as long it's freely falling under gravity but not when you hit the ground.
反过来说,如果你得到一个结果,发现似乎是错的,那么你就应该回过头来问问自己,我是不是违反某些前提了,这个模型中,你就发现,只要质点在重力作用下自由下落,质点具有加速度a的前提是正确的,但是落地后就不成立了
应用推荐