And we plug in our values and end up with mv squared mv^2/r-Ze^2/ over r minus Ze squared over And I am going to call this equation two.
我们最后的结果,就是,我把这称为方程式二。
I know the energy in this first pair would equal -e^2 That is just going to equal minus e squared over 4 pi epsilon zero r naught.
我们明白第一对的能量将会等于,等于,/4πε0,R圈。
If you want to write it as a vector equation, you want to write it as v square over r minus-- I want to say that it's pointing in the direction toward the center.
如果要写出矢量方程,就应该写成 -v^2 / r,也就是说,方向就向圆心
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