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And the solution to this equation looks like this where it is written in terms of a quantity called a wavefunction.
这个方程的解法是,看起来像是写成数学符号就是,波函数。
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The notion here is that you can get a globally optimal solution from locally optimal solutions to sub-problems.
这里的概念是你可以通过,子问题的局部最优方案,得到全局优化解决方案。
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Suppose f of x, y, z equals k1, that is my equation, s1 and it gives me a solution s1.
假设我的方程是这样，然后给出了一个解。
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So sometimes the extra solution is very interesting and you should always listen to the mathematics when you get extra solutions.
所以有时候这些增根的意义很耐人寻味,当你解出增根的时候,别忘了想一想它的数学含义
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They're stuck to a surface that's provided by the environment that's around them, they're not swimming free in solution.
他们黏联在,周围环境的表面上,而不会在溶液中自由运动
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And on Monday what we were discussing was the solution to the Schrodinger equation for the wave function.
周一我们讨论了,薛定谔方程解的波函数。
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There is obviously no magic solution to this question but the best answer I know of is Socrates.
这个问题,没有神奇的解答,但我认为最佳的答案是苏格拉底。
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As I see it, there is only one solution to all the foregoing difficulties.
在我看来，解决这种困境只有一个办法。
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The solution to that might be a kind of amnesia, a kind of progressive lack of memory.
也许可以用健忘症来解决，一种持续的记忆缺失。
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So actually, this is a winning solution.
所以，这实际上是个成功的解决方式。
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But if you can accept the purity of the statement I just made, it is at the root of the thing you have a solution.
但如果你能够遵从原教旨主义的方式,那么这就是你解决此问题的根本
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So in this case, the communication worked but am I right in thinking that the communication isn't such an instant solution as it was in the game we saw last time?
在这个博弈中,交流起到了作用,但是能说这和上一讲的博弈一样吗,交流并没能直接给出解决的方案
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That's the whole point of the solution.
这就是那个方案的要点。
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Why? Bundle of properties: mechanical strength, chemical inertness, ease of fabrication: that's not a unique solution.
为什么，属性的总和：,机械强度，化学惰性，易于制造，那不是独特的解决方法。
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OK, so what have I done? I just added a little bit more now. I'm now running through a pair of loops. Again notice the encapsulation, that nice abstraction going on, which is what I want. Once I get to this stage though by the way, there might be more than one solution.
我现在运行了一对循环,再一次注意这个封装,抽象得很好，这就是我想要的结果,我按这种方式走到这一步的时候,可能会有多组答案。
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STUDENT: So, how do you come to a conclusion as to which you should use then, if you can determine the size based on solution, or based on input, so how do you decide?
学生：所以，你怎样决定你该用,哪个来算呢？现在如果你可以选择是，基于解决方案的大小，还是基于输入的大小，你应该怎样决定呢？
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