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And for sake of argument, there are no amputees among the chickens and the pigs.
它走到农地里然后它看到了,20个头和56只脚。
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Four times the number of pigs plus two times the number of chickens, assuming they're not next to a nuclear reactor, is 56.
其它还有什么呢？,4倍的猪的数量加上两倍的鸡的数量,考虑到它们不是住在核反应堆旁的。
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And the question is, so how many pigs does he have, and how many chickens does he have? Wow. What a deep problem, right? But you're going to see why we're going to use this in a second. So you know how to solve this, this is a fifth-grade problem, right?
为了避免歧义，这些猪和鸡都是健全的,现在问题是它到底有多少只猪和鸡呢？,多深刻的一个问题啊，对吗？,但是你将要看到的是,我们为什么要举这个例子,你知道如何解答这个问题？
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System of linear equations. What are the equations here? Well, I could say, you know, the number of pigs plus the number of 20 chickens equals 20, right? Because we've got 20 heads. And then what else do I have?
如何解决这个问题呢？,用线性方程式的办法来解决，等式是什么呢？你应该知道,猪的数量加鸡的数量等于,对吧？因为我们有20个头？
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I've got two chickens and eighteen pigs, you get the idea.
我有1只鸡和19只猪，这能行吗？,我有2只鸡和18只猪。
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pigs chickens will be the second part.
第一部分是。
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is run a FOR loop here. I'm going to let the number of chickens be in this range.
我知道怎么做对吧？写一个小循环,我所需要做的就是运行一个for循环。
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