We're going to be counting the number of basic steps it takes to solve the problem.
我们还要去数着,解决问题的的基本步骤有多少。
you want to solve the problem for the other person.
你就想帮别人解决问题。
I'm going to let t of b be the number of steps it takes to solve the problem of size b.
我会设立一个t作为,计算指数为b的时候解决问题需要的步骤数。
then we won't be able to solve the problem.
我们也没法解决这个问题。
In some ways I think that that's because the poem Lycidas seems in some ways to solve the problem of Milton's waiting, this problem that he has of needing to wait.
就某些方面而言,我认为是因为,看起来以某种方式解决了弥尔顿耽搁多时,却又的确有等待的必要的问题。
So, I'm raising this not to solve the problem.
我说这些并不是为了解决问题
It literally halves the amount of time it takes to solve that problem but we can actually do better.
它能把解决问题时间的缩短一半,但其实我们能做的更好。
So, the problem we have to solve to help people like MikeIs to find ways to cause those parts of cortex to develop properly when they are children or have them re-learn as adults.
因此,我们要帮助像迈克这样的人解决的问题,就是找到他们在儿童时期使,这些皮层进行发展,或者成年以后再学习的方法。
We don't have to worry about how you solve it, but it's problem in mathematics and the answer will be--surprise, it's going to be oscillating back and forth and that'll come out of the wash.
我们没必要去担心这个方程该怎么解,但这个数学问题的答案将会是令人惊讶的,弹簧会来回振荡,问题就迎刃而解了
So at the very same moment that positing the nonsplitting of souls seems to solve the fission problem of duplication, it yanks the rug out from underneath the soul theorist by undermining one of the types of arguments for believing in the soul in the first place.
所以在为了解决复制产生的裂变问题,营造出灵魂的不分割性时,也侵蚀了一开始相信灵魂的存在的论据,从内部动摇了灵魂理论者。
OK. Binary search is perhaps the simplest of the divide and conquer algorithms, and what does that mean? It says, in order to solve a problem, cut it down to a smaller problem and try and solve that one.
好了,二分搜索也许是,最简单的分治算法,这意味着什么?,也就是说,为了解决一个问题,把它切割成小的问题,然后再来一个个解决。
That doesn't solve the problem we had before though Then I'm going to append it, and keep the last change for future use.
这样没有解决我们之前的问题,所以我要给它加上一个值,让上一次的变化能够用到未来的例子中。
So you see a problem like this in the real world; you see a problem on campus you might want to solve.
在现实生活中你会遇到这样的问题;,在学校里看到这种问题时,你会想要去解决它。
That's a lot harder of a problem to solve if you need to reconstruct the fragmentation, yeah.
如果你需要重构这些碎片,会有很多很难的问题等着我们。
So when you're trying to think about is this a problem that I can solve with dynamic programming, these are the two questions you ask.
所以当你想知道能否,用动态编程来解决这个问题时,你可以问自己两个问题。
So if I were to solve this problem, here's the way I would do it. I would say, first thing I want to do, is I want to input a value for the base as a float.
如果我想要解决这个问题,这就是我要解决它的方式了,第一件我要做的事情就是要,输入一个浮点数作为三角形的底。
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