If we overlay what the actual molecular orbital is on top of it, what you see is that in the center you end up cancelling out the wave function entirely.

如果我们把真实的分子轨道覆盖在上面，你可以看到中间的,波函数是完全抵消掉了。

麻省理工公开课 - 化学原理课程节选

So now that means if this is where the center of positive excess charge lies and on top of it is the center there is no displacement of the charge so there is no net dipole.

所以现在我们说,如果正电荷中心,就位于,那么还是在这里负电荷中心也在这里,所以没有空间偶极。

麻省理工公开课 - 固态化学导论课程节选

Top is better than bottom against left -- sorry, bottom is better than top against left because 6 is bigger than 5, but top is better than bottom against center because 11 is bigger than 0.

在左列下,选上比选下,我说错了,在左列下选下比选上要好,因为6大于5,但在中列下,选上比选下好,因为11大于0

耶鲁公开课 - 博弈论课程节选

If Player I chose top, center yields 3, right yields 0: 3 is bigger than 0.

如果参与者I选择上,选中的收益是3,选右的收益为0,3大于0

耶鲁公开课 - 博弈论课程节选

It involves two players and we'll call the Players I and II and Player I has two choices, top and bottom, and Player II has three choices left, center, and right.

此博弈有两个参与人,分别为I和II,参与人I有两个选择,上和下,参与人II有三个选择,左中右

耶鲁公开课 - 博弈论课程节选

So Player I's payoff, if she chooses top and Player II chooses center, we read by looking at the top row and the center column, and Player I's payoff is the first of these payoffs, so it's 11.

参与人I的收益,如果她选上,参与人II选中,我们来看一下上行和中列,参与人I对应第一个收益即11

耶鲁公开课 - 博弈论课程节选

Player II's payoff, from the same choices, top for Player I, center for Player II, again we go along the top row and the center column, but this time we choose Player II's payoff, which is the second payoff, so it's 3.

在这种情况下参与人II的收益,即参与人I 选上参与人II选中时,注意下是上行和中列,但是现在我们要找参与人II的收益,也就是第二个收益,即3

耶鲁公开课 - 博弈论课程节选