• There is a Homburg and there is a Borsalino, Here's Bohr mixing it up with royalty.

    一个是汉堡,一个是博尔萨利诺,这是波尔和皇室人员。

    麻省理工公开课 - 固态化学导论课程节选

  • At my maximum, I'll put a hat over it to indicate this is the argmax; at my maximum I'm going to set this thing equal to 0.

    给每个最大值都标注上一个来,在最大值处导数方程等于0

    耶鲁公开课 - 博弈论课程节选

  • Here's one climbing out of the pool: First her face appeared, long and cadaverous, with a bandage-like bathing cap coming down almost to her eyes, and sharp teeth protruding from her mouth.

    有一个女人从游泳池中出来了,首先是她的脸,修长,而惨白,如绷带般的泳从她的头部,耷拉到她的眼睛,锋利的牙齿从她的口中突出。

    耶鲁公开课 - 1945年后的美国小说课程节选

  • Why not just put our own orgasmitron hat on with a little-- not rat lever, but now human lever-- with the electrodes stimulating our own brains so that we get this intense burst of pleasure?

    我们为何不带上电子高潮-,把老鼠杠杆变成人类杠杆-,用电极刺激我们的大脑,获得强烈的快感?

    耶鲁公开课 - 死亡课程节选

  • And h with the carrot or the hat here, well, that carrot or hat tell us it must be an operator, and this is called the Hamiltonian operator.

    而且带的H,好,这个告诉我们它肯定是一个算符,这个被称为哈密顿算符。

    麻省理工公开课 - 化学原理课程节选

  • Pretend the hat isn't there a second.

    暂时先不要考虑这里的

    耶鲁公开课 - 博弈论课程节选

  • To make this a first order condition, I'm going to say "at the best response," put a hat over the 1.

    为了达到一阶条件,我说在最佳对策下,在S1上写个

    耶鲁公开课 - 博弈论课程节选

  • I know that Player 2's best response for every possible choice of Player 1, which if we had done it would be q2 hat is going to a -c over 2b--q1 over 2, right?

    参与人1不同策略下参与人2的最佳对策,即q2等于/2b - q1/2

    耶鲁公开课 - 博弈论课程节选

  • So the best response for Player 1, as a function of what Player 2 chooses, q2, is just equal to the q1 hat in this expression and if I solve that out carefully, I will no doubt make a mistake, but let's try it.

    这个就是参与人1的最佳对策,它是参与人2策略q2的一个函数,它和之前的q1那个表达式是相等的,虽然我是很仔细地计算的,还是有可能算错的,我来验证一下

    耶鲁公开课 - 博弈论课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定