• So, the x axis is interatomic spacing, and the y axis is energy.

    所以x轴是原子间距,而y轴是能量值。

    麻省理工公开课 - 固态化学导论课程节选

  • It's going to hug the x axis until it gets a very, very close.

    它将会紧挨x轴,直到很近很近。

    麻省理工公开课 - 固态化学导论课程节选

  • We're going to take an entity that lives along the x axis.

    我们拿一个只能沿着X轴运动的质点

    耶鲁公开课 - 基础物理课程节选

  • Let's create a graph here that on the x axis it's going to be time, so time zero will be when you first take in a food and then one hour later, two hours later will be shown as you go from left to right, and then we'll have blood glucose level up on the y axis.

    我们在这建立一个曲线图,X轴代表的是时间,所以零时间点是你第一次进食的时间,然后一小时以后,两小时以后,是从左到右呈现在图表上的,在Y轴上是你的血糖值

    耶鲁公开课 - 关于食物的心理学、生物学和政治学课程节选

  • The highest probability now is going to be along the x-axis, so that means we're going to have a positive wave function every place where x is positive.

    概率最高的地方是沿着x轴,这意味着只要在x,大于零的地方波函数都是正的。

    麻省理工公开课 - 化学原理课程节选

  • Another way to represent a point in a plane is I've got a radius and I've got an angle from the x-axis, right, and that's a standard thing you might do.

    平面上面的点的方法,也就是极坐标,上面那种方法其实是,如果你们喜欢我这么说的话,笛卡尔坐标表示法。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • which is f , divided by the value of the x-axis here.

    斜率,而f是p趋于0时pV的极限。

    麻省理工公开课 - 热力学与动力学课程节选

  • The motion is just along the x axis.

    只有 x 轴方向的运动

    耶鲁公开课 - 基础物理课程节选

  • You might think it's all along x and somebody can tell me it's all along my new y axis.

    你可以认为它是沿着 x 轴的,也有人会说它是沿着新的 y 轴的

    耶鲁公开课 - 基础物理课程节选

  • That's a choice, and that choice turns out to be very interesting and really important, because if you connect these two points together, you get a straight line that has to intercept the x-axis at some point.

    在这一选择下,我们会发现一件非常有趣,而且极其重要的事,当你把这两点用直线连接起来,你会发现这条直线,将与x轴在某点相交。

    麻省理工公开课 - 热力学与动力学课程节选

  • We said, "Let's take, for the simplest case that we can possibly imagine, namely a particle moving in one dimension along the x-axis with a constant acceleration a.

    我们说过,"考虑我们可以想象的最简单的情况,即质点在一维空间运动,沿着 x 轴且保持恒定加速度 a

    耶鲁公开课 - 基础物理课程节选

  • You cannot answer that, even if I promised to move only along the x-axis, because I think...I don't want to pose this as a question, because I think the answer is fairly obvious to everybody.

    即使我保证只在 x 轴上移动,你们仍然无法回答,因为我觉得...我不想将其作为一个问题,因为我认为答案是显而易见的

    耶鲁公开课 - 基础物理课程节选

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