蛋白质的总含量即可由含氮量乘以常数6.25算出。
So total protein content can be determined by multiplying nitrogen by the factor 6.25.
因为我们需要的量，是由这个量乘以一个常数，因为这个量是零，因此我们需要的量也是零。
And that implies that since the quantity we want is given by this quantity, which is zero times a constant, the quantity we want is also zero.
换句话说，任意时刻A物质的浓度等于初始浓度，减去常数乘以时间。
In other words, the concentration of at any time is given by the initial concentration, t minus the rate constant times time.
所以，你们不可以再这么说，“哦，我只要在dudv前乘以一个常数就可以了”。
So, it's not true that you can just say, oh, I'll put a constant times dudv.
这个常数是纯物质的蒸汽压，乘以液相的组分，Raoult定律。
Which is the vapor pressure of the pure material times the, and the composition of the liquid phase, Raoult's law.
你可以把其中一个,写成另外一个乘以某个常数，而这个常数,通常就表示为希腊字母λ，我不知道你们见过没有。
You can write one of them as a constant times the other one, and that constant usually one uses the Greek letter lambda. I don't know if you have seen it before.
然后C有一个很小的二次方的上升，接着指数的上升直到你预期的饱和,那C约等于A0乘以1减,的负k2乘以时间次方，e，to，the，minus，k2，times，time。,速率常数k2长时间地起主导作用。
And then C has a very small quadratic rise, followed by the exponential rise to saturation that you'd expect. So C is approximately a0 times one minus e The rate constant k2 dominates the long times.
一开始将电子电荷平方，再除以光速和普朗克常数，然后将总数乘以2个圆周率。
You start with the square of an electron's charge, divide it by the speed of light and Planck's constant, then multiply the whole lot by two PI.
我们写下了，晶格能等于负的马德隆常数,乘以阿伏伽德罗常数，乘以q1q2除以4πε
And we wrote something that looks, the energy is equal to minus the Madelung constant times Avogadro's number, 0R0 q1 q2 over 4 pi epsilon zero R zero.
我们可以发现有效的z等于n的平凡，乘以电离能除以里德堡常数,这些所有再开方，所以等于n乘以,除以RH整体的平方根。
So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.
这些离散的值乘以整数，乘积因子,是普朗克常数除以2π,其中n可以取1，2，3，等等。
n It takes discrete values, multiples of some integer n, and the multiplication factor is the ratio of the Planck constant divided by 2 pi where n takes one, two, three and so on.
焦耳每个原子，或者，如果乘以，阿伏伽德罗常数你会得到焦耳数每摩尔。
It is joules per atom. Or, if you multiply by Avogadro's number then you will get joules per mole.
发现带电粒子以电荷群的作用力为向心力做圆周运动时，有一常数乘以频率等于带电粒子的动能。
It finds that there is a constant multiplied by frequency which is equal to the kinetic energy, when a charged particle does circular motion for the centripetal force product by the charge group.
获取鼠标轮已转动的制动器数的有符号计数乘以wheel_delta常数。
Gets a signed count of the number of detents the mouse wheel has rotated, multiplied by the WHEEL_DELTA constant.
获取鼠标轮已转动的制动器数的有符号计数乘以wheel_delta常数。
Gets a signed count of the number of detents the mouse wheel has rotated, multiplied by the WHEEL_DELTA constant.
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