... algebraic fraction代数分式;代数分数式 algebraic inequality代数不等式 algebraic number代数数 ...
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...xpression)61第四节因式分解(Factorable Expression)61第五节方程(Equations)63第六节代数不等式(Algebraic Inequalities)68第七节数学归纳法70第八节极限70第九节函数(Functions)71第十节重点试题精练及解析72第三章文字题(Word Problems)86第一节...
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Re: 代数不等式 ( Algebraic Inequalities-Old and New methods )中文版习题 感谢!
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代数不等式在中职 Vocational & Technical Education Forum
在文章的最后,笔者给出了解代数不等式的一些教学建议。
In the end of the article, the author here makes some Suggestions on how to solve the inequalities in teaching students.
分别给出含根式的一个几何不等式和一个代数不等式的指数推广。
This paper intends to give the generalization with exponent respectively about a geometric inequality and an algebraic inequality containing radical expression.
利用排序不等式重证了一个代数不等式,并在此基础上得出了新的结论。
An algebra inequality is reproved by using sequencing inequality, from which some new conclusions are deduced.
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