同理可得 (arccos x )′ = 2 1 x 1 . (arctan x )′ = 2 1+ x 1 .
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...在,且 ′(t ) ≠ 0 ,则 1 1 x 2 (arcsin x )′ = d arcsin x = dx dy ψ ′(t ) = dx ′(t ) ( ′(t ) ≠ 0) 二阶导数 (arccos x )′ = 1 1 x2 d arccos x = 1 1 x2 dx (arctan x )′ = [ln(x + ( 1 1+ x2 (arc cot x )′ = 1 2 1+ x x +a 2 2 d arctan x = )]...
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