And if we go on to step three where we figure out how many we would need for full octets, it's just going to be 2 times 8, so we have 16.
而如果我们继续到第三步,判断一下填满所有“八隅体“需要多少个价电子,结果应该就是二乘以八,也就是十六个。
So this isn't-- OK. And you're also close. It's going to be linear but how many times do I go through this?
每次能丢掉一半,所以这里不是-,好的,但你也很接近了,他可能是线性的,但我得遍历多少次呢?
The end is hard and it's going to be hard, no matter how you come to it.
结束很难,并且一定会很难,无论你打算怎样结束。
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