Then if you fast forward to 2005 and look at the average return that was posted for 2000,it was +1.2%.

如果把时间快进至2005,5年后公报的2000年平均收益,变成了1.2%

耶鲁公开课 - 金融市场课程节选

1 So, it's two times 3.12 plus four times 1.31, 6 all divided by six.

就是2*3。12+4*1。,最后再除以。

麻省理工公开课 - 固态化学导论课程节选

So if we have total +2 and complete shielding -1 where that can actually negate a full positive charge, because remember our nucleus is plus 2, +1 one of the electrons is minus 1, so if it totally blocks it, all we would have left from the nucleus is an effective charge of plus 1.

抵消一个完全的正电荷,因为记住我们的原子核是,其中一个电子是,所以如果它完全挡住了它，我们从原子核中留下的，全部有效电荷就是，所以，在我们的第一个例子中,我们的第一种极端情况。

麻省理工公开课 - 化学原理课程节选

As reported contemporaneously in 2000,the number was -3.1% but if you look at the number reported for 2005, because bad records had disappeared and good records had been added, all of a sudden the average experience for that year went up to +1.2%.

000年期的公告中这个数字为负3.1%,但是如果你去查2005年公告的数字,坏记录已经调整而消失,有利的投资记录被加入,转瞬之间,年平均收益升至1.2%

耶鲁公开课 - 金融市场课程节选

So it'll be 1 plus 1/4 times 4, 1/4 times 4 is 1, so 1 plus 1 is 2, so Player II's best response in that case will be 2.

这回就是1+4/4,即1+1=2,所以此时参与人II的最佳对策是2

耶鲁公开课 - 博弈论课程节选

I think you can tell by analogy with what I did in one dimension that the position of that object at any time t is going to be the initial position plus velocity times t plus one half a t square.

你们可以类比一下我在一维情况下的结论,这个物体在任意时刻 t 的位移,等于初始位移,加上 v ? t + 1/2 ? a ? t^2

耶鲁公开课 - 基础物理课程节选

One minus one-half plus one-third, it is all there.

-1/2+1/3，这就是它。

麻省理工公开课 - 固态化学导论课程节选

We can just rewrite that, if I divide through by 2 and rearrange, it's going to tell me that ?1, or if you like, ?1 is equal to 1 plus B S2.

我们这么写,如果我除以2然后整理,可以得出?1等于1+B*S2

耶鲁公开课 - 博弈论课程节选

So similarly, I would find that ?2 2 equals 1 plus B S1 and this is the best response of Player II, as it depends on Player I's choice of effort S1.

同理可得?2等于1+B*S1,?2是参与人II的最佳对策,因为它与参与人I的策略S1有关

耶鲁公开课 - 博弈论课程节选