.. You want to get it-- if you keep adding assets, you can do better and better on your portfolio standard deviation.
你想得到-,如果不断增加资产,组合的标准差就会越来越小。
But we can do better than that.
但我们可以想出更好的解释。
It literally halves the amount of time it takes to solve that problem but we can actually do better.
它能把解决问题时间的缩短一半,但其实我们能做的更好。
What can you do to these faces, these average faces, ? and make them look even better?
你能对怎样处理这些大众脸,让他们看起来更好?
Are there resources that we can go to to help us do this work better?
您能否告诉我们一些我们能寻找到并帮助我们,将这件工作做得更好的资源?
So the psychological reading doesn't do any better,as far as I can see.
所以心理学的解读也不够好。
But luckily, we can do a little bit better than that.
幸好我们还可以做更深入的研究
Depending on where the assets expected returns are and the assets' standard deviations, we can see that we might be able to do better than--have a lower variance than either asset.
根据资产的预期收益,以及收益的标准差,可以看到我们有更好的选择,这里的方差值比以上两种方案都要低。
I say this in all my classes, I've published thousands of pages on different subjects, all of you can do it better, because you can do it from your own point of view you can do it afresh, you have new resources you are different people, you belong to different generations.
在每一门课上我都会这么说,我在不同课题上都,发表过许多文章,你们都可以做得更好,因为你们可以从自己的角度来做,你们可以做新鲜的,你们有新的资源,你们是不同的人,你们属于不同的一代人。
This is very important,which is why I am doing it: "If we want to know how fast a human being can run, then it is no use to average out the speed of a "good sample" of the population; it is far better to collect Olympic gold medal winners and see how well they can do.
这话非常重要,是我作这个研究的原因:,“如果想知道人类最快能跑多快,那从好的样本中测出平均数是“,没用的;,而应该收集田径类奥运冠军的信息,看他们能跑多快。
If we can sort things, you know, we get this n log n behavior, and we got a n log n behavior overall. But can we actually do better in terms of searching.
如果我们可以排序,如你所知,我们有n,log,n级别的算法,并且我有一个整体的n,log,n级别的算法,但是我们在搜索方面可以做的更好吗?
He's a better teacher than Scotus or Aquinas, and the text seems almost to suggest that Milton can't do without his own teacher, Edmund Spenser.
他是一位比苏格拉底和阿奎那更好的良师,这些文章几乎暗示了弥尔顿,没有老师埃蒙德·斯潘塞则不能做到弃绝那些诱惑。
Who can deviate and do better here?
谁能偏离并且胜过他
Actually, we can do it a little better than that, since we know the game is symmetric, we know that S1* is actually equal to S2*.
实际上我们能得出更多,因为我们知道这个博弈是对称的,我们知道S1*=S2
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