so I'm heating up the system in this path here, and then to connect the 2 endpoints here, a constant temperature path.

需要再用，一个等温过程，这两个状态。

麻省理工公开课 - 热力学与动力学课程节选

So what I'm doing here is I'm cooling, and then when I'm sitting at a fixed volume and I'm increasing the pressure, what am I doing? I'm heating, right?

对了，因此在这里，需要冷却,而在这里，当体积不变增加压强时？

麻省理工公开课 - 热力学与动力学课程节选

Now to make that happen, it's not adiabatic, right. If I wanted to do that, I'd need a heating element or something to cool, so I could make that temperature change happen, right.

要实现这点，它就不会是绝热的，对吧，如果我想做到这点,我需要一个加热元件或什么制冷的东西,这样我才能让温度变化。

麻省理工公开课 - 热力学与动力学课程节选

And on the other side of that temperature you end up heating if you compress.

而在另一边的温度上,压缩气体将导致升温。

麻省理工公开课 - 热力学与动力学课程节选

And that gives rise to the heating that you can actually measure.

我们可以看到,它造成的温度升高。

麻省理工公开课 - 热力学与动力学课程节选

That's going to be your heating up of the gas.

这样气体的温度将会升高。

麻省理工公开课 - 热力学与动力学课程节选

So I'm doing cooling and heating cycles.

需要怎么做？加热，对吧？

麻省理工公开课 - 热力学与动力学课程节选

Or I could have a non-adiabatic, I could take the same temperature change, by taking a flame, or a heat source and heating up my substance. So, clearly q is going to depend on the path.

也能改变温度，绝热指的是没有热传递，在非绝热条件下，也同样可以升温,比如用火或者热源加热，这样，q也应当与路径有关。

麻省理工公开课 - 热力学与动力学课程节选