so I'm heating up the system in this path here, and then to connect the 2 endpoints here, a constant temperature path.
需要再用,一个等温过程,这两个状态。
That's going to be your heating up of the gas.
这样气体的温度将会升高。
Or I could have a non-adiabatic, I could take the same temperature change, by taking a flame, or a heat source and heating up my substance. So, clearly q is going to depend on the path.
也能改变温度,绝热指的是没有热传递,在非绝热条件下,也同样可以升温,比如用火或者热源加热,这样,q也应当与路径有关。
And on the other side of that temperature you end up heating if you compress.
而在另一边的温度上,压缩气体将导致升温。
应用推荐