The amount of work you've put in to get here depends on the path. It's not a function of state.
这些量就能,决定系统的状态了。
I just realized that education was kind of the path that I wanted to go on.
最后意识到我想接着做教育这一行。
So if I take p times V to the gamma, anywhere on the path, it's going to be equal to the same relation This is going to be true for any point on the path.
结果都,将等于,初态点的,只要在这条路径上。
I knew from the relatively limited set of course offerings that my school had the things I felt I was good at and so I went off on the path.
从相对有限的课程设置里我得知,学校里有我擅长的科目,所以我走上了这条道路。
So there's a return branch on every possible path through the code. And that's valuable, it's something you want to think about as your right your own.
所以代码中每条可能的路径,都会有一个返回值分支,这是非常有价值的,当你自己写程序的时候也应该考虑这件事。
Unencumbered by, I guess, the conventional wisdom, we started out at Yale on a path that I think is--fundamentally that changed the way that institutions manage portfolios.
抛开惯常思维和传统做法,我们在耶鲁开创了一条新路,一条我认为,从根本上,改变了机构投资管理方式的新路
The biggest thing for me on that path is I needed to draw something out and I needed to get it out of my head.
在我看来,这条路上最重要的莫过于,是需要描绘出一些东西,再把它们忘却。
Reverse transcriptase is a naturally occurring protein, it has a biological function in HIV, but we can use it for a technical logical function here by going backwards on the biological path from messenger RNA to DNA.
反转录酶是在自然环境中存在的蛋白质,它在HIV中发挥着生物功能,但在这里它可以发挥一个技术功能,让它用信使RNA反转录出DNA
This depends on the path. It tells you right here the path is constant pressure. These don't depend on the path, right. V doesn't care how you v get there. u doesn't care how you get there.
这由变化的具体路径决定,这个小脚标表明过程是恒压的,这些量都与具体路径无关,即不管是通过什么路径使得体积变化为Δ
Or I could have a non-adiabatic, I could take the same temperature change, by taking a flame, or a heat source and heating up my substance. So, clearly q is going to depend on the path.
也能改变温度,绝热指的是没有热传递,在非绝热条件下,也同样可以升温,比如用火或者热源加热,这样,q也应当与路径有关。
They happen to be on the path.
任意的两个点。
The reason for inexact doesn't mean it's a crummy measurement, t means that it's path dependent, and so the value of this integral depends on how you get from one to two.
这是因为它是,与积分路径有关的,因此这里的积分值,取决于从一端到二端的,具体路径。
So any point I pick on that path will be equal to p1, V1 to the gamma.
也就是说路径上面任取一个点,计算p,V^γ
So if you need the help of the notes it's in there but I would urge you to work through it on your own, and it's the following: let's start with the same path A, all right?
如果你需要帮助,可以去看讲义,但我还是希望你们自己去推导它,它是这样的,让我们从:,相同的路径A开始,好吗?
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