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The second way to have something that is net nonpolar is to have spatially symmetric disposition of polar bonds.
第二种构成,需要空间非极性,就是需要极性键的空间对称分布。
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Even though the best response is pretty complicated-- and by the way, obviously the things are symmetric for Payer II.
虽然最佳对策是很复杂的,顺便说一下 选手2的情况也明显是这样
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You have a symmetric molecule, and let's see.
一个非常对称的分子，再看看。
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Also, it is cylindrically symmetric around the bonding axis, so this is how we know that it's a sigma orbital.
此外，它关于键轴是圆柱对称的，这就是为什么我们知道它是sigma轨道。
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That's an example of symmetric sequence and it happens that most restriction enzymes also recognize those spaces.
这是一个对称序列的例子,大多数限制性内切酶都能识别这些序列
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If I now hybridize these, if I take these and I make four symmetric, now, these are just the sp3 orbitals.
如果我将他们杂化，然后形成4个对称的轨道，这就是sp3轨道。
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So, somehow we have to figure out a way to take orbitals that are non-symmetric, and convert them into orbitals that are symmetric.
所以有时我们需要找到一个方法,让不对称的轨道，转变为对称的轨道。
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Same bond, symmetric bonds means equal energy, which means equal links.
相同的对称的化学键意味着相等的能量，相同的联系。
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Just to point out in passing, up to now, we've been looking mostly at symmetric games.
顺便说一下,到目前为止,我们所学的大部分是对称博弈
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We somehow have to take hydrogen, attach it to carbon, and we have to make it symmetric, and we have to make it nonpolar.
我们需要把H接到C周围，而且我们需要让它是对称，且非极性的。
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And yet, the molecule is symmetric and nonpolar.
所以这个分子是对称非极性的。
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Notice this game is not symmetric in the payoffs or in the strategies.
但注意此博弈的策略与收益是非对称的
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It's perfectly symmetric.
它是完全对称的。
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The thing is still not dominated and we could still have done exactly the same analysis, and actually you can see I'm not very far off in the numbers I made up, but things are not perfectly symmetric.
这虽然不能成为劣势策略,但我们还是能得出一样的分析结果,实际上这和我编的数字相差也不是很远,凡事并不总是绝对对称的嘛
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Player II has three choices, this game is not symmetric, so they have different number of choices, that's fine.
参与人II有三种选择,这个博弈不是对称的,所以他们可选策略数量不同,这无所谓
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It makes sense to draw the wave function as a circle, because we do know that 1 s orbitals are spherically symmetric.
把波函数画成一个圆是有道理的，因为我们知道1s轨道是球对称的。
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This is the effort cost. Similarly, player II, everything's symmetric here Player II's payoff is the same thing.
这是她的努力成本,由对称可得,参与人II的收益是一样的
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Now I could go through again and do exactly the same thing for Player II, but I'm not going to do that because everything's symmetric.
如果我照此计算同理可得参与人II的,我就不算了,因为都是对称的
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Most restriction enzyme also recognize symmetric sequences of DNA, GAATTC for example.
大多数限制性内切酶,也能识别DNA的对称序列,例如GAATTC
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Actually, we can do it a little better than that, since we know the game is symmetric, we know that S1* is actually equal to S2*.
实际上我们能得出更多,因为我们知道这个博弈是对称的,我们知道S1*=S2
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