Why doesn't the copy constructor get called?
为什么不复制构造函数被调用？
Why does this code invoke the copy constructor?
为什么这段代码调用复制构造函数？
How to call to the copy constructor from the copy-assignment operator?
如何从复制赋值运算符调用复制构造函数？
The compiler is eliding the call (actually, two calls) to the copy constructor.
编译器是省略调用（实际上，两与复制构造函数调用）。
Listing 2 shows a piece of code that results in a compile-time error because the copy constructor is private.
清单2显示了产生编译时错误的代码部分，因为该拷贝构造函数是私有的。
The assignment operator is applied on a initialized object, but this is not the case in the copy constructor.
赋值运算符是应用于一个初始化的对象，但这并不是拷贝构造函数的情况下。
The noncopyable class definition presents no surprises, as the copy constructor and operator= are declared private.
noncopyable类定义没有什么令人感到新奇的地方，因为copy constructor和operator= 声明为 private。
How else could you use that return instruction to create and return an object and yet not use the copy constructor?
不然你怎么使用返回指令创建并返回一个对象而不使用复制构造函数？
If you do not write a correct code for the copy constructor, object within a list will have some data members uninitialized.
如果你没有为拷贝构造函数写正确的代码，就有可能造成list中对象的某些数据成员没有初始化。
When I return by value from an assignment operator, firstly what is the mechanism and basis of calling the copy constructor?
当我返回值赋值操作符，首先是调用复制构造函数为基础的机制？
When it can do so, the compiler is permitted (but not obligated) to skip the copy constructor and create the object directly.
当这种用法被支持时，编译器被允许(但不被制强)跳过复制构造函数而直接创建该对象。
The only other thing to note in Listing 17 is that the definitions for the copy constructor and operator= methods are not provided.
清单17中要注意的另一点是，未提供copy constructor和operator=方法的定义。
The copy constructor is a special kind of constructor which creates a new object which is a copy of an existing one, and does it efficiently.
拷贝构造函数是一种特别的构造函数，用于复制已经存在的对象到新生成的对象，这是一种高效的方式。
To manage a class with pointer members, we must define all three copy-control members: the copy constructor, assignment operator, and the destructor.
为了管理具有指针成员的类，必须定义三个复制控制成员：复制构造函数、赋值操作符和析构函数。
Each class whose instance will go into the container must implement at least the copy constructor it is good to implement also the assignment operator.
每个类(其实例要在容器内使用)必须至少实现拷贝构造函数(实现赋值运算符，也是好习惯)。
To resolve C2299, do not make the copy constructor or assignment operator a template function, but rather a non-template function that takes a class type.
若要解决C2299，请不要使复制构造函数或赋值运算符成为模板函数，而使其成为采用类类型的非模板函数。
You do not need a copy constructor, and you need never sweat the gory details of implementing a clone method.
您不需要使用复制构造函数，并且永远也不需要大汗淋漓地去实现clone方法的那些令人惨不忍睹的细节。
Default copy constructor does a very simple operation, they will do a bit-wise (member-wise) copy of an object, which means that the object will be copied bit by bit.
如果程序员没有提供拷贝构造函数，那么编译器会自动生成默认的拷贝构造函数。默认的拷贝构造函数会执行简单的操作，即按位拷贝对象。
Your first solution conveys to the reader that the copy-constructor is private and is not to be used.
你的第一个解决方案向读者传达，拷贝构造函数是私有的，不能使用。
The traditional way to solve this is to declare the copy-constructor private and to leave it unimplemented.
传统的方式来解决这个是声明拷贝构造函数私有和未实现的。
We all know that the implicit copy constructor operates as follows: default construct all member variables, then assign each member variable the appropriate corresponding value.
我们都知道，这个隐式的拷贝构造函数操作如下：默认构建所有成员变量，然后分配每个成员变量相应的对应值。
Because a template constructor is never a copy constructor, the presence of such a template does not suppress the implicit declaration of a copy constructor.
由于模板构造函数终究不是拷贝构造函数，因此这种模板的出现并不会隐藏原来隐含的拷贝构造函数之声明。
Many developers write the first constructor and then copy and paste the code into other constructors, to satisfy the multiple overrides defined in the class interface.
很多开发者编写第一个构造函数，然后将代码复制粘贴到其它构造函数中去，以满足在类的接口上定义的多个重载。
You didn't define a copy constructor so a default one was created by the compiler.
你没有定义复制构造函数，默认的是由编译器创建的。
Even though an implementation is allowed to elide the copy, a viable and accessible copy constructor (or move constructor, if we're talking about a move) should still be present.
虽然实现是允许省略拷贝，一个可行的和可访问的拷贝构造函数(或移动构造函数，如果我们谈论的是一个移动)应该是仍然存在的。
Question: Manually writing a copy constructor which initializes each member variable as a copy is very tedious, and verges on ridiculous as the number of member variables grows.
问题：手动编写一个拷贝构造函数的初始化每个成员变量作为副本很乏味，和近乎荒谬的成员变量数量的增加。
In the first case, you are essentially declaring a private copy constructor and then not providing any implementation.
在第一种情况下，你基本上是声明一个私有拷贝构造函数，然后没有提供任何实现。
The idea is to create a protected copy constructor aside from the default constructor.
保护的想法是创建一个拷贝构造函数除了默认构造函数。
Add output statements to the constructor, destructor and copy constructor to see the effect of the Named Return Value optimization when you run the program.
将输出语句添加到构造函数、析构函数和复制构造函数，以查看在运行程序时命名返回值优化的效果。
Add output statements to the constructor, destructor and copy constructor to see the effect of the Named Return Value optimization when you run the program.
将输出语句添加到构造函数、析构函数和复制构造函数，以查看在运行程序时命名返回值优化的效果。
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