• The principal square root function is defined using the nonpositive real axis as a branch cut.

    主平方根函数是使用非正实轴作为分支切割定义的。

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  • This example returns the square root of a numeric literal.

    此示例返回数值的平方根。

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  • where (with pi = 3.1415... and sqrt() denoting the square root)

    其中 (pi = 3.1415...,sqrt()表示平方根)

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  • I want to then do, I need to find the square root b squared plus h squared, right?

    我接下来要求b的平方和h的平方,的和的平方根对不对?

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  • Filter all of the target number's factors from 1 to the square root of the number.

    过滤目标数的所有因子,从1到其平方根。

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  • You also send a fault response if someone requests the square root of a negative number.

    如果有人请求负数的平方根,也将发送错误响应。

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  • But the system variance is going to be on the order of the square root of N times epsilon.

    但是系统能量的变化量大约,会是N的平方根乘以ε

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  • I did a demonstration to show you that the time is proportional to the square root of h.

    我那次只不过是一个演示,用以证明时间,与根号h成正比。

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  • Can you do the math: What is one hundred times four, divided by the square root of a hundred?

    你会做数学吗:100乘4除以100的平方根是多少呢?

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  • The first line defines a function called square that takes an argument and emits its square root.

    第一行定义一个名为square的函数,该函数可接受参数并发出其平方根。

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  • Subtract a constant from a vector's magnitude (shorten the vector) without using square root?

    减去一个常数向量的大小(缩短向量),而不使用平方根?。

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  • The params element contains one param element that contains a double whose square root is desired.

    params元素包含一个param元素,param元素包含double, double的平方根是希望得到的值。

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  • When the Angle is small, the saturation control is replaced by the reverse square root control.

    小角度调转时用反向开方代替饱和控制的三模态控制。

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  • For example, for the number 16, the square root is 4, which inadvertently gets added to the list twice.

    例如,对于数字16,平方根是4,该数字将被意外地添加到列表中两次。

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  • It loops through all of the integers that are less than or equal to the square root of the input integer.

    对输入的整数求平方根,遍历所有小于或等于平方根的整数。

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  • If you can harvest factors in pairs, you need only check factors up to the square root of the target number.

    如果您成对获取因子,您只需要检查到目标数的平方根即可。

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  • Each observation could have been weighted inversely as the distance or as the square root of the frequence.

    每次观测可以倒过来加权作为距离或作为频率的平方根。

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  • Double square root (DSR) equation has provided a new theoretical framework for developing wave equation migration.

    双平方根(dsr)方程为波动方程偏移提供了一种新的理论框架。

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  • This script computes the square root of 5, but since it doesn't store or display the result, it is not very useful.

    这个脚本计算了5的平方根,但没存储下来,也没有显示出来,所以就根本没用了。

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  • First, I take the range of numbers from 1 to the target number's square root plus 1 (to make sure I catch all the factors).

    首先,获取数的范围是从1到目标数的平方根加 1(确保能取到所有因子)。

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  • Remember that the method Math.sqrt returns a double, which is therefore only an approximation of the actual square root.

    记住方法Math . sqrt返回的是一个double型,也就是说这只是一个大概值。

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  • You may think that the uncertainty in there equals the square root 1 of 372 plus or minus 1 1 divided by 186 plus or minus 1.

    你也许认为这个误差,=372加减1的,平方根1,除以186加减。

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  • If you want to escape from this, you will need a speed which is the square root of two times larger than that orbital velocity.

    如果想要逃离这里,你将需要一个速度,是轨道速度2倍大的,平方根。

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  • Then the intent is to take the square root; however, this works only if the display type of the field is Number as shown in figure 8.

    则目的是求平方根;但是仅当字段的显示类型是Number(如图8所示)时才能工作。

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  • The code in Listing 5 first gathers the list of factors up to the square root of the target number, saving it in the factors variable.

    清单5中的代码首先将该因子列表收集到目标数字的平方根,将其保存在factor变量中。

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  • And the good news was we didn't have to worry about how math did square root or anything like that, we just got it and we used it.

    也可能是其他数,好消息是,我们不必担心math函数是怎样开方的,我们只要使用它就好。

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  • It turns out that when you harvest the Numbers in pairs, you accidentally grab Numbers twice when you reach a whole-number square root.

    结果是当您成对地获得数字时,您在到达整数平方根时将意外地获得两次数字。

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  • The period, which is 2 pi times the square root of l over g, if you substitute in your length of 5.1 meters, you will find 4.57 seconds.

    周期,等于2π,乘以l/g的平方根,如果把长度为5。1米,代入,会得到4。57秒。

    youdao

  • The period, which is 2 pi times the square root of l over g, if you substitute in your length of 5.1 meters, you will find 4.57 seconds.

    周期,等于2π,乘以l/g的平方根,如果把长度为5。1米,代入,会得到4。57秒。

    youdao

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