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And what we find out is the wavelength of a Matsuzaka fastball is 1.1 times 10 to the -31 meters.
我们算出松阪快球的波长,是1，1乘以10的负31次方米。
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8 You will see if you get --I think the delta here is 1.78, 8 which is roughly 1.8.
我认为电负性差值应该是1。,约等于1。
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And this one will be particularly germane to a portion of Problem Set 1, at least in Problem Set 1.
这个程序跟习题集1中的,一部分比较相似，至少在习题1中。
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And the Former Prophets include the books of Joshua, Judges, 1 and 2 Samuel, 1 and 2 Kings. They read as a historical narrative.
前先知书》包括《约书亚书》《士师记》,《撒母尔书1-2》《列王记1-2》它们被当作史料。
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And again, we're not saying choosing 2 beats choosing 1, 2 wins against 1 or 9 wins against 10.
我们不是说选立场2会击败选立场1的,选立场2能赢立场1的,或者选立场9能赢选立场10的
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So 1.1 times 10 to the -31 meters is not, in fact, a significant number when we're comparing it, for example, to the length of a ball, or the size of the baseball field.
所以1，1乘以10的负31次方米，事实上并不是一个很重要的数字，举例来说，当它与一个球的长度，或者一块棒球场地对比时。
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If you had $1 to invest you can borrow $.50 and invest in a $1.50 worth of stocks.
比如你有1美元进行投资,你可以透支0。5美元,投资价值1。5美元的股票。
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And the thing you should notice here is that it's doing a lot of the same things over 2 1 and over again. So, for example, we'll see 2, 1 2 1 here. And 2, 1 here.
在这里你要注意的是,它不断在重复同样的工作,例如我们看这里的1,还有这里的。
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They expect 2 - 1 = 1 and when 2 - 1 = 2 or 3 or 0, they look longer, indicating surprise.
它们认为2-1=1,所以当2-1=2或3或0,他们注视时间更长,表明了惊奇
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One that's . 2 kilobases long and one that's 1.1 kilobases long - kilobase is 1,000 bases.
一段长0.2千碱基,另一段长,1.1千碱基,千碱基指一千个碱基
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And the constant, if we redo it in modern SI units, 1 would take on the value of 1.1 1*10^7m-1 times 10 to the 7th reciprocal meters.
如果我们用现代国际单位制来改写它，这个值是1,1。
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But if my pair chooses Beta then Alpha yields -1, Beta yields 1: in this case Beta would be better.
但是要是我对手选β我选α得-1,选β得1,此时选β更好
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1%10 So if you actually do in a program 11 percent 10, 1 what you'll get back is 1 because that is in fact the remainder of that arithmetic operation.
如果在编程里就是，返回,因为1是这个计算式的余数。
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PROFESSOR: And I didn't write up there but it is one, 1 and we can see that it's 1, 2 because it's 1/2 of 2, 4 minus 2, so 1/2 of 2, the bonding order is going to be equal to one.
教授：我没有写出来，但是是1，我们可以看到为什么是，因为它等于1/2的2，4减去，所以1/2的2，键序等于1。
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Well, the reason, the way that we can check it is just to see if it's in between our two extreme 1 cases. We know that it has to be more than 1, because even if we had total shielding, 1 we would at least feel is the effective of 1.
好的我们可以检查它的原因和方式是观察,它是否在我们的两种极端案例之间,我们知道它必须大于，因为即使如果我们有完全的屏蔽，我们最小感到的有效值是。
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0 So if you do for instance 11 divided by 10 in grade school, 1 that's 1 with the remainder of 1.
举个例子，11除以，得1余。
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